The gas in a balloon occupies 2.25 L at 298 K and 300 kPa. At

1 answer:

5 0

If a gas in a balloon occupies 2.25 L at 298 K and 300 kPa, the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.

<h3>How to calculate temperature?</h3>

The temperature of an ideal gas can be calculated using the following formula:

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure
P2 = final pressure
V1 = initial volume
V2 = final volume
T1 = initial temperature
T2 = final temperature

According to the information given in this question;

P1 = 300kpa = 2.96 atm
P2 = 2.17 atm
V1 = 2.25L
V2 = 3.50L
T1 = 298K
T2 = ?

2.96 × 2.25/298 = 2.17 × 3.5/T2

0.022T2 = 7.595

T2 = 7.595 ÷ 0.022

T2 = 345.23K

Therefore, if a gas in a balloon occupies 2.25 L at 298 K and 300 kPa. the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.

Learn more about temperature at: brainly.com/question/11464844

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6 0

3 years ago

For the reaction so3 + h2o h2so4, calculate the percent yield if 500. g of sulfur trioxide react with excess water to produce 57

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The % yield if 500 g of sulfur trioxide reacted with excess water to produce 575 g of sulfuric acid is calculated using the below formula

% yield = actual yield/ theoretical yield x100

actual yield =575 grams
to calculate theoretical yield
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= 500g/ 80 g/mol =6.25 moles

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by use of mole ratio of SO3 : H2SO4 which is 1:1 the moles of H2SO4 is also= 6.25 moles

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How does an increase in volume affect equilibrium

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