Answer:
0.000435
Explanation:
Because it is 10-4, you move the decimal place to the left four times. this will result in 0.000435.
Answer:
D) 4.97M
Explanation:
firstly we will calculate the molar mass of K2HPO4.
K=39, H=1 , P=31, O=16
K2HPO4 = (39*2)+(1)+(31)+(16*4) =174g/mol
number of moles = mass / molar mass
mass of K2HPO4 =238g
number of moles = 
moles.
moles is contained in 275mL of solution.
The molarity of a solution is the number of moles of solute contained in 1000mL of solution.
if moles is contained i 275mL of solution
Then X will be contained in 1000 mL of solution
x=4.9739moles
x ≈ 4.97moles
4.97moles is contained in 1000mL of solution.
The molarity of the solution is 4.97M
Answer:
J
Explanation:
Heat is measured in Joules (J)
Answer:
C₂H₃O₂
Explanation:
Assume that you have 100 g of the compound.
Then you have 40.68 g C, 5.08 g H, and 54.24 g O.
1. Calculate the <em>moles of each element</em>.
Moles of C = 40.68 × 1/12.01 = 3.387 mol C
Moles of H = 5.08 × 1/1.008 = 5.010 mol H
Moles of O = 54.24 × 1/16.000 = 3.390 mol O
===============
2. Calculate the <em>molar ratios</em>.
Divide all values by the smallest number.
C: 3.387/3.387 = 1
H: 5.010/3.387 = 1.479
O: 3.390/3.387 = 1.001
===============
3. <em>Multiply each ratio by 2
</em>
C: 2 × 1 = 2
H: 2 × 1.479 = 2.958
O: 2 × 1.001 = 2.002
===============
4. Determine <em>the empirical formula</em>
Round off all numbers to the closest integer.
C: 2
H: 3
O: 2
The empirical formula is C₂H₃O₂.
Answer:
Same # of protons.
Explanation:
It's right cuz I took the test like last year and I still remember the answer
