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Inessa [10]
2 years ago
9

What is metallic character​

Chemistry
1 answer:
Natalka [10]2 years ago
4 0

Answer:

<h3>METALLIC CHARACTER </h3>

<h3>DEFINITION </h3>

  • The metallic character is a property that is unique to metals. It indicates the reactivity of a metal atom

Explanation:

HOPE IT'S HELPFUL THANKS

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seraphim [82]

Various structures, or allotropes, of carbon, are precious stone, graphite, and fullerenes. In jewel, every carbon iota is attached to four other carbon iotas, shaping an unbending construction that makes precious stones hard.

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K + Cl2 -&gt; KCI <br> Balance equation
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Answer:

2K + Cl2 -> 2KCl

Explanation:

Just balancing :3

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What is the total energy change for the following reaction:CO+H2O-CO2+H2
Alekssandra [29.7K]

Answer:

\large \boxed{\text{-41.2 kJ/mol}}

Explanation:

Balanced equation:    CO(g) + H₂O(g) ⟶ CO₂(g) + H₂(g)

We can calculate the enthalpy change of a reaction by using the enthalpies of formation of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)

(a) Enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{CO(g)} & -110.5 \\\text{H$_{2}$O} & -241.8\\\text{CO$_{2}$(g)} & -393.5 \\\text{H$_{2}$(g)} & 0 \\\end{array}

(b) Total enthalpies of reactants and products

\begin{array}{ccr}\textbf{Substance} & \textbf{Contribution)/(kJ/mol})&\textbf{Sum} \\\text{CO(g)} & -110.5& -110.5 \\\text{H$_{2}$O(g)} &-241.8& -241.8\\\textbf{Total}&\textbf{for reactants} &\mathbf{ -352.3}\\&&\\\text{CO}_{2}(g) & -393.5&-393.5 \\\text{H}_{2} & 0 & 0\\\textbf{Total}&\textbf{for products} & \mathbf{-393.5}\end{array}

(c) Enthalpy of reaction \Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)= \text{-393.5 kJ/mol - (-352.3 kJ/mol}\\= \text{-393.5 kJ/mol + 352.3 kJ/mol} = \textbf{-41.2 kJ/mol}\\ \text{The total enthalpy change is $\large \boxed{\textbf{-41.2 kJ/mol}}$}

4 0
3 years ago
Which of the following is a synthesis reaction?
blsea [12.9K]
Number 1 is a synthesis reaction because two compounds/elements are coming together to form one compound
5 0
3 years ago
Una garrafa contiene 9L de gas a 18°C y 780torr. ¿Cuál será la masa de este gas que finaliza con una densidad de 2g/L a 80°C y 1
marin [14]

Respuesta:

14,9 g

Explicación:

Paso 1: Calcular los moles de gas

Una garrafa contiene 9 L de gas a 18°C (291 K) y 780 Torr. Podemos encontrar los moles de gas (n) usando la ecuación del gas ideal.

P × V = n × R × T

n = P × V/R × T

n = 780 torr × 9 L/(62,4 Torr.L/mol.K)/ × 291 K = 0.387 mol

Paso 2: Calcular la masa molar del gas

El gas tiene una densidad (ρ) de 2 g/L a 80 °C (353 K) y 1,5 atm. Podemos calcular la masa molar (M) del gas usando la siguiente fórmula.

ρ = P × M / R × T

M = ρ × R × T / P

M = 2 g/L × (0.082 atm.L/mol.K) × 353 K / 1,5 atm = 38,59 g/mol

Paso 3: Calcular la masa del gas (m)

Usaremos la siguiente formula.

m = n × M = 0.387 mol × 38,59 g/mol = 14,9 g

7 0
3 years ago
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