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MrRissso [65]
2 years ago
11

HELPPPyall please help my sister won't help me ​

Chemistry
1 answer:
ira [324]2 years ago
3 0

\text{H}_3\text{PO}_4  + 3\text{KOH}  \longrightarrow \text{K}_3 \text{PO}_4     +3\text{H}_2 \text{O}\\\\10\text{Na} +2 \text{NaNO}_3  \longrightarrow 6\text{Na}_2 \text{O} + \text{N}_2\\\\\  2\text{H}_3 \text{PO}_4 + 3\text{Mg(OH)}_2 \longrightarrow \text{Mg}_3(\text{PO}_4)_2+6\text{H}_2 \text{O}\\\\2\text{Al(OH)}_3 + 3\text{H}_2 \text{CO}_3 \longrightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{H}_2 \text{O} \\\\2\text{C}_6\text{H}_6+15\text{O}_2 \longrightarrow 12\text{CO}_2 +6\text{H}_2 \text{O}\\

\text{Pb(OH)}_2 +2\text{HCl} \longrightarrow \text{PbCl}_2 +2 \text{H}_2 \text{O}

2\text{Mn} + 6\text{HI} \longrightarrow 3 \text{H}_2+2\text{MnI}_3

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NeTakaya

sorry i don't know the answer i'm really sorry

7 0
2 years ago
The specific heat of aluminum is 0.897j/(g•°C). If a 22.6 g sample of aluminum is heated from 25°C to 250°C, then how much heat
Oxana [17]

Q=mcat

=(22.6)(.897)(250-25)

4,561.245 or 4.5 * 10^-3

3 0
3 years ago
Guys- my science teacher doesn't teach, he just says go on schoology ​
Free_Kalibri [48]
The relative mass of each element can be found from the periodic table (the larger number). For instance, P2O5, P = 31.0 O = 16.0, thus the formula mass (Mr) is 2(31) + 5(16) = 142 amu (atomic mass unit). I used a not really specific periodic table. Maybe your teacher is referring to open Schoology (a website where teacher can post files or announcements to students in his or her class). Sorry if i got something mistaken.
5 0
2 years ago
If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
kodGreya [7K]

Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}

[Cu^{2+}]=0.041 M

Best regards!

6 0
2 years ago
Populations have some genetic {blank}
Juliette [100K]
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Populations have some genetic variation.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0
3 years ago
Read 2 more answers
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