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2 years ago

HELPPPyall please help my sister won't help me

Chemistry

1 answer:

ira [324]2 years ago

3 0

$\text{H}_3\text{PO}_4 + 3\text{KOH} \longrightarrow \text{K}_3 \text{PO}_4 +3\text{H}_2 \text{O}\\\\10\text{Na} +2 \text{NaNO}_3 \longrightarrow 6\text{Na}_2 \text{O} + \text{N}_2\\\\\ 2\text{H}_3 \text{PO}_4 + 3\text{Mg(OH)}_2 \longrightarrow \text{Mg}_3(\text{PO}_4)_2+6\text{H}_2 \text{O}\\\\2\text{Al(OH)}_3 + 3\text{H}_2 \text{CO}_3 \longrightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{H}_2 \text{O} \\\\2\text{C}_6\text{H}_6+15\text{O}_2 \longrightarrow 12\text{CO}_2 +6\text{H}_2 \text{O}\\$

$\text{Pb(OH)}_2 +2\text{HCl} \longrightarrow \text{PbCl}_2 +2 \text{H}_2 \text{O}$

$2\text{Mn} + 6\text{HI} \longrightarrow 3 \text{H}_2+2\text{MnI}_3$

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Ductile means...

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Diano4ka-milaya [45]

Answer:

$\large \boxed{109.17 \, ^{\circ}\text{C}}$

Explanation:

Data:

50/50 ethylene glycol (EG):water

V = 4.70 gal

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Calculations:

The formula for the boiling point elevation ΔTb is

$\Delta T_{b} = iK_{b}b$

i is the van’t Hoff factor — the number of moles of particles you get from 1 mol of solute. For EG, i = 1.

1. Moles of EG

$\rm n = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{1000 mL}}{\text{1 L}} \times \dfrac{\text{1.11 g}}{\text{1 mL}} \times \dfrac{\text{1 mol}}{\text{62.07 g}} = \text{159 mol}$

2. Kilograms of water

$m = 0.50 \times \text{4.70 gal} \times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{998 g}}{\text{1 L}} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{8.88 kg}$

3. Molal concentration of EG

$b = \dfrac{\text{159 mol}}{\text{8.88 kg}} = \text{17.9 mol/kg}$

4. Increase in boiling point

$\rm \Delta T_{b} = iK_{b}b = 1 \times 0.512 \, \, ^{\circ}\text{C} \cdot kg \cdot mol^{-1} \, \times 17.9 \cdot mol \cdot kg^{-1} = 9.17 \, ^{\circ}\text{C}$

5. Boiling point

$\rm T_{b} = T_{b}^{\circ} + \Delta T_{b} = 100.00 \, ^{\circ}\text{C} + 9.17 \, ^{\circ}\text{C} = \mathbf{109.17 \, ^{\circ}C}\\\rm \text{The boiling point of the solution is $\large \boxed{\mathbf{109.17 \, ^{\circ}C}}$}$

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Why do warm currents begin near the equator?

r-ruslan [8.4K]

Answer:

I would go with A

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A covalent compound that shares two pairs of electrons.<br> What is it?

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The two oxygen atoms share two pairs of electrons, so two covalent bonds hold the oxygen molecule together

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HELPPPyall please help my sister won't help me ​

HELPPPyall please help my sister won't help me