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nikdorinn [45]
2 years ago
5

The astronomer who first worked out the mathematical description of black hole event horizons was?

Physics
1 answer:
vovangra [49]2 years ago
4 0

Karl Schwarzschild devised the first general relativity model that would adequately describe a black hole in 1916.

What is Black Hole?

A black hole is an area of spacetime with such intense gravitational pull that nothing can escape from it, not even light or other electromagnetic waves. According to general relativity theory, a compact enough mass can bend spacetime into a black hole. The event horizon is the line beyond which there is no escape.

Black holes were once thought to be a mathematical curiosity, but theoretical research in the 1960s revealed that they were actually a general prediction of general relativity.

To know more about Black Hole refer:

brainly.com/question/7866362

#SPJ4

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True or false? Scientific theories lack experimental support
goldenfox [79]

Answer:

Hey there!

It is false. Theories can be repeatedly tested to give people an explanation of the world.

Let  me know if this helps :)

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Is orange juice in an orange potential energy or kinetic energy?
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Potential energy. Kinetic energy is movment
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Two students suggest different functions for the battery plays a flashlight.
irga5000 [103]

Answer:

Student b

Explanation:

Because, Battery pumps the charges around the circuit. Here, charges are the free electrons. And this charges are already present in the conductor. When we connect this conductor with the battery - It set up an electric field and The diffrence between the potential between the ends of the wire pushes this free charges to move in perticular direction. (This is called electric energy)

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What is the net force on a water bottle?
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3 years ago
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A cyclist is riding a bicycle at a speed of 22 mph on a horizontal road. The distance between the axles is 42 in., and the mass
stealth61 [152]

Answer:

The shortest distance is  S = 24.86 ft

Explanation:

The free body diagram of this question is shown on the first uploaded image

From the question we are told that

   The speed of the bicycle is v_b = 22\ mph = 22 * \frac{5280}{3600}   =  32.26 ft/s

     The distance between the axial is  d = 42 \ in

The mass center of the cyclist and the bicycle is m_c = 26 \ in  behind the front axle

The mass center of the cyclist and the bicycle is m_h = 40 \ in above the ground

   For the bicycle not to be thrown over the

     Momentum about the back wheel must be zero so

                \sum _B = 0

=>             mg (26) = ma(40)

=>             a = \frac{26}{40} g

Here  g = 32.2 ft/s^2

     So     a =  \frac{26}{40} (32.2)

             a =  20.93 ft/s^2

Apply the equation of motion to this motion we have

       v^2 = u^2 + 2as

 Where  u = 32.26 ft /s

             and v = 0 since the bicycle is coming to a stop

        v^2 = (32.26)^2 - 2(20.93) S

=>      S = 24.86 ft        

                 

5 0
3 years ago
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