Question

2. Two charged particles as shown in figure below. QP = +10 μC and Qq = +20 μC are separated by a distance r = 10 cm. What is the magnitude of the electrostatic force.

Answer 1

Answer:

F = 180 N

Explanation:

Given that,

Charge, q₁ = 10 μC

Charge, q₂ = 20 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

$F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 10\times 10^{-6}\times 20\times 10^{-6}}{(0.1)^2}\\F=180\ N$

So, the magnitude of the electrostatic force is 180 N.