Impulse is the change in momentum. So you just have to subtract 300 -280
The answer would be 20kgm/s
The distance between object P1 and its image formed is determined as 36 m.
<h3>
Distance of the image</h3>
The distance of the image formed by object P1 is calculated as follows;
In a plane mirror; object distance = image distance
image distance of P1 = 18 m
distance between object and image = 18m + 18 m = 36 m
Thus, the distance between object P1 and its image formed is determined as 36 m.
Learn more about plane mirrors here: brainly.com/question/1126858
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B-Pitcher C-Catcher H-Strike I-Umpire G-Strike Zone E- Foul Ball F- Ball J- Pick-off D-Error A- Shortstop. I think (Sorry for them being out of order. I had to break them down)
Answer:
the electric field strength of this charge is two times the strength of the other charge
Explanation:
Using the relationship between electric field and the charge, which is inversely proportionality. Let the the magnitude of the first charge be Q and the respective electric field be E. It implies that;
E1/E2 = Q2/Q1
E2 = E1 x Q1/Q2
= E x Q/ (Q/2)
= 2E
Answer:
The volume of the bubble near the surface will be 9.47 m³
Explanation:
Given that,
Depth = 52.0 m
Volume = 1.50 m³
Temperature at bottom = 5.5°C
Temperature at the top = 18.5°C
We need to calculate the pressure at the depth 52.0 m
The pressure is
Where, = Pressure at the surface
= Pressure at the depth
Put the value into the formula
We need to calculate the volume of the bubble just before it reaches the surface
Using equation of ideal gas
Now, The equation of at bottom and top
Put the value into the formula
Hence, The volume of the bubble near the surface will be 9.47 m³