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Ainat [17]
3 years ago
10

The waste products of a nuclear fusion power plants can be best described as

Physics
2 answers:
I am Lyosha [343]3 years ago
4 0

They can be described as small in quantity and very dangerously radioactive.

qwelly [4]3 years ago
3 0

Fusion you say ? Fusion ?

The products left over after fusion are:

-- Helium (harmless)

-- Hydrogen that never got fused

-- Water (from Hydrogen that combined with some stray Oxygen that leaked in)

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a particle moves along the x axis with an acceleration of a=18t, where a has units if m/s2. if the particle at time t=0 is at th
ludmilkaskok [199]

Answer:

 Position at t= 4 seconds is 144 m

Explanation:

 It is given that acceleration, a = 18 t, where t is the time.

 We know that Velocity, v = \int { a} \, dt

  Substituting value of a,

           Velocity, v = \int {18t} \, dt=\frac{18t^2}{2} +c=9t^2+c

 We know that at t = 0, v = -12 m/s

         So, 9*0^2+c=-12\\ \\ c=-12m/s

So velocity, v = (9t^2-12)m/s

  We also know that displacement, x = \int { v} \, dt

     Substituting value of v,  

        Displacement, x=\int {(9t^2-12)} \, dt=\frac{9t^3}{3} -12t+c=3t^3-12t+c

  We know that at t = 0, particle is at origin, x =0.

               So,  0=3*0^3-12*0+c\\ \\ c=0

   Displacement, x = 3t^3-12t

At t = 4 seconds

   x = 3*4^3-12*4=192--48=144m

Position at t= 4 seconds is 144 m  

4 0
3 years ago
The velocity of waves in a ripple tank is 10 centimeters per second, and standing waves are produced with nodes spaced 3.0 centi
Vsevolod [243]
<span>node spacing = half of wavelength = 3 cm velocity = 10 cm/s = freq * wavelength hench freq = 10/6 = 5/3 = 1.7 hz</span>
6 0
4 years ago
Read 2 more answers
Can you help and explain these for me?
ollegr [7]
Yes I can do you want me to
8 0
3 years ago
A person consumes a snack containing 14 food calories (14kcal). what is the power this food produces if it is to be "burned off"
Inessa05 [86]

Answer:

B) 2.7W

Explanation:

Converting Cal to Joule

        1 cal = 4.186J

        14 kcal = 14 x 1000 x 4.186

                     = 58604 J

Converting hour to seconds

             6 hours = 6 x 60 x 60 seconds

                           = 21600 seconds

Power is the time rate of doing work.

Power = Work/Time

P = (58604) / (21600)

P = 2.7W

8 0
3 years ago
Read 2 more answers
The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc
Law Incorporation [45]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is r=6940 km=6.94 \cdot 10^6 m, the gravitational force is F=9.21 \cdot 10^4 N and the mass of the Earth is m_1=5.98 \cdot 10^{24} kg, therefore we can rearrange the previous equation to find m2, the mass of the telescope:
m_2 =  \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg
6 0
3 years ago
Read 2 more answers
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