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IgorC [24]
2 years ago
14

100 points please help

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
3 0
36x^2+60x+25=(12x+5)(3x+5)
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Estimate the sum by first rounding each
sukhopar [10]
5 3/8 rounds to 5,
4 7/10 rounds to 5
Your estimated sum is 10
5 0
3 years ago
Positionx (m)
9966 [12]

Answer:

A. 3.0 m/s

Step-by-step explanation:

Based on the graph,

velocity = Area of the graph

v =  \frac{y1 - y2}{x1 - x2}

(y : position and x : time)

Let y1 = 2m and y2 = 14m,

t1 = 0s and t2 = 4s

v = (14 - 2)m/(4-0)s

= 12m/4s

= 3.0 m/s

6 0
3 years ago
Read 2 more answers
Solve the equation. 33 = p – 6.71<br> A. –39.71 <br> B. –26.29 <br> C. 39.71 <br> D. 26.29
jeka57 [31]

<u>Answer</u>

C. 39.71


<u>Explanation</u>

33 = p - 6.71

The first step is to make the like terms to be on the same side.

Add 6.71 on both sides of the eqution

33 +  6.71 = p - 6.71 + 6.71

39.71 = p


∴ p = 39.71

4 0
3 years ago
Ella has 0.5 lbs of sugar. How much water should she add to make the following concentrations? Tell Ella how much syrup she will
HACTEHA [7]

Ella has to add 32.833 lbs of water to get 33.333 lbs of syrup.

<u>Solution:</u>

Ella has 0.5 lbs of sugar. Let x lbs be the amount of water Ella should add to get the 1.5% of syrup,

\Rightarrow0.5\text{ lbs }- 1.5\%

\Rightarrow x+0.5\text{ lbs }- 100\%

On writing the proportion,

\Rightarrow\dfrac{0.5}{x+0.5}=\dfrac{1.5}{100}\\ \\\Rightarrow0.5\cdot 100=(x+0.5)\cdot 1.5\\ \\\Rightarrow50=1.5x+0.75\\ \\\Rightarrow1.5x=50-0.75\\ \\\Rightarrow1.5x=49.25\\ \\\Rightarrow x=\dfrac{49.25}{1.5}\approx 32.833\ lbs

To get 1.5% syrup Ella should add 32.833 lbs of water. The total weight of syrup is 33.333 lbs.

7 0
3 years ago
At a local seaside, a vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50. The vendor stocks a maxim
guapka [62]

Answer:

The answer is below

Step-by-step explanation:

Let x represent the number of single cone ice cream and let y represent the number of double cone ice cream.

Since the vendor stocks a maximum of 70 single cones and a maximum of 45 double cones. hence:

0 < x ≤ 70, 0 < y ≤ 45      (1)

The vendor expects to sell no more than 50 ice creams, hence:

x + y ≤ 50

Plotting the constraint using geogebra online graphing tool, we can see that the solution to the problem is at (5, 45)

Since the vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50, hence:

Revenue = 3x + 4.5y

At the point (5, 45), the revenue is:

Revenue = 3(5) + 4.5(45) = $217.5

5 0
3 years ago
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