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AlekseyPX
3 years ago
9

What does it mean to draw a model for 8/10

Mathematics
1 answer:
Lyrx [107]3 years ago
7 0
Draw ten boxes and mark out eight
You might be interested in
Solve for y, given that b=22(Round your answer to 1 decimal place, if necessary.)
timurjin [86]

Answer:

37.7

Step-by-step explanation:

First, we have to divde 22/7 to find the scale factor. I chose 22 and 7 because those two sides are ocngruent. We get 3.14. We then have to multiply 12 by 3.14 beacuse that is the side that is congruent with the side y. When you multiply you should get 37.68. Since we have to round we get 37.7.

5 0
3 years ago
A clothing company buys t-shirts for $10 and sells them for $100. What is the percentage mark up on
Mice21 [21]

Answer:

900%

Step-by-step explanation:

Starting price : 10

End price: 100

100-10 = 90

90/10 = 9 = 900%

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0
3 years ago
A cube has a volume of 64 cm3. What is the length of a side of a cube
Reil [10]

Answer:

V=8cm

Step-by-step explanation:

V=a³

a=∛64


7 0
4 years ago
How do I divide numbers by using long division. <br>​
Vsevolod [243]

The only rule to follow is

Divide dividend by divisor and the mention the quotient and things left after remains in place of remainder

Here is a sample

\sf\Large\qquad\quad16\\ \begin{array}{cc} \cline{2 - 2}\sf 20 )&\sf \ 327\\&\sf - 20 \downarrow\\ \cline{2-2}& \sf \ \ \ \ 127\\ &\sf \ - 120 \\ \cline{2-2} & \sf \ \007 \\ \cline{2-2} \end{array}\\\\\\ \sf Divisor \rightarrow 20 \\ \\ \sf Quotient \rightarrow 16\\\\ \sf Remainder \rightarrow 7

3 0
2 years ago
Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a
spin [16.1K]

Answer:

Mean = 68.9

s^2 =18.1 --- Variance

Step-by-step explanation:

Given

\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5

For 59 - 66

x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5

For 67 - 74

x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5

For 75 - 82

x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5

For 83 - 90

x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5

So, the table becomes:

\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}

The mean is then calculated as:

Mean = \frac{\sum fx}{\sum f}

Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}

Mean = \frac{2547.5}{37}

Mean = 68.9 -- approximated

Solving (b): The sample variance:

This is calculated as:

s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}

So, we have:

s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}

s^2 =\frac{652.8}{36}

s^2 =18.1 -- approximated

5 0
3 years ago
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