Considering a scenario in which the Sun is going to explode.
In order to escape the explosion, we depart in a spacecraft with a speed of v = 0.8c.
The star Tau Ceti is 12 life years away.
At the midpoint of the journey, the Sun as well as Tau Cetik explode. at the same instant.
Imagine a hermit who is immobile with respect to both the Sun and Tau Ceti and resides on an asteroid that is midway between both. He observes the blast waves of both explosions as our spaceship passes him. This observer concludes that the two stars blew up simultaneously because he believes both stars to remain stationary.
In the frame of reference, the Sun and Tau Ceti explode at the same time and will remain stationary.
Learn more about the frame of reference here:
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I'll do that with pleasure. But first, we seriously need to discuss part-A.
The answer to part-A is used to solve part-B, and you don't have it yet.
I loved the way you set up part-A ... started out with the formula you'll use
to solve it, then listed the given information neatly, and substituted the given
information into the formula. All of that was so beautifully laid out ... with
units and everything, which hardly anybody ever does ... that I didn't notice
the absurd result at first.
Angie ! Take two steps back and look over part-A ! You multiplied
(200 and something) by (100 and something), and got an answer of
(200 and something) ! What's up with that ? ! ?
Everything outside the box is correct and beautiful ... units and everything.
Inside the box should be 30,021 kg-m/s .
NOW we're equipped to work on part-B:
You start out with F = m a .
That's the best formula to use for roughly 99.9% of these motion problems ...
but not for this one, sadly.
Here's what you need for part-B. Again, I love the way you start out listing
the formula you're going to use, and all the data you know.
But I think the whole subject of 'Impulse' temporarily slipped your mind.
Here's a quick review:
-- (force) acting for (some limited time) is called "Impulse".
-- The magnitude of impulse is (force) x (time).
-- Impulse is a vector. The direction of impulse is the direction of the force.
-- Look at the units. (I wouldn't do this with anyone else, but you're different ...
you have an understanding and appreciation for units.)
force = 'newton' = kg-m/s²
time = second
Impulse = (force) · (time)
= (kg-m/s²) · (sec) = kg-m/s . Same units as momentum !
It turns out that the amount of impulse is exactly the amount of
change in momentum !
You push on an object with (some force) for (some time).
Then you stop pushing and you let the object go on its way.
The impulse you delivered to the object is (force) x (time), and that's
exactly how much momentum you gave it !
NOW ... The motorcycle has 30,021 kg-m/s of momentum.
In order to stop it ...
that's how much momentum it needs to lose.
OR
that's how much impulse you have to give it, opposite to its motion.
(Force) x (time) = 30,021 kg-m/s
Divide each side
by t = 0.05 sec: Force = (30,021 kg-m/s) / (0.05 sec)
= (30,021 / 0.05) kg-m/s²
= 600,423 newtons
(roughly 135,000 pounds)
(That's why a motorcycle crash
can often mess up your hair.
Or worse. )
Can you add an image of the work
Answer:
see solution below
Explanation:
The given resistors are connected in series.
Equivalent resistance in series = 30 + 55 + 15
Equivalent resistance in series Rt = 100 ohms
Since the potential difference in the circuit = 36V
Get the current in the circuit first
I = V/Rt
I = 36/100
I = 0.36A
Get the voltage across 30ohms resistor;
V30 = 0.36 * 30
V30 = 10.8volts
Hence the voltage across the 30ohms resistor is 10.8volts
Get the voltage across 55ohms resistor;
V55 = 0.36 * 55
V55 = 19.8volts
Hence the voltage across the 55ohms resistor is 19.8volts
Get the voltage across 15ohms resistor;
V15 = 0.36 * 15
V15 = 5.4volts
Hence the voltage across the 15ohms resistor is 5.4volts
