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Ludmilka [50]
3 years ago
15

Ultraviolent radiation is one of many types of energy that comes to Earth from the Sun.

Physics
2 answers:
Leni [432]3 years ago
7 0
True. UV radiation is a form of energy that travels through space. <span>The sun is a major source of ultraviolet radiation but also emits a number of different types of electro magnetic radiation.</span>
motikmotik3 years ago
7 0
True. It is the cause of some types of skin cancer, unlike the heat and light waves.
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Esercizio 1
timama [110]

Explanation:

can u please translate it to english language. I can't understand.

7 0
3 years ago
Use Kepler's third law to find the planet's average distance (semimajor axis) from its star. (Hint: Because the mass of the star
konstantin123 [22]

Answer:

Explanation: The planet average distance = 42300km

Kepler's 3rd Law also known as the Harmonic Law states that;

for each planet orbitting the sun, its side real period squared divided by the cube of the semi-major axis of the orbit is a constant.

A planet, mass m, orbits the sun, mass M, in a circle of radius r and a period t. The net force on the planet is a centripetal force, and is caused the force of gravity between the sun and the planet.

Please find the attached file for the solution

3 0
3 years ago
Ben climbs a tree to retrieve a lost football. If he does 2,400 J of work to climb 8 m, how much force is he using?
krok68 [10]
Work = Force * distance.
d = 8 m
W = 2400 J
F = ???

2400 = 8 * F
F = 2400/8
F = 300 N


6 0
3 years ago
Can someone please explain how to solve 13?
frozen [14]

Hello!

Everything you've done so far seems to be correct. However, you need to get rid of the sin. To do this, use ssin^{-1}.

This is known as the inverse of sin, which is where you go from a fraction to the actual angle itself.

When you run sin^{-1}(1/5) through a calculator, you get about 11.537 degrees, or θ = 11.537.

To verify this, all you need to do is run sin (11.537), and the calculator returns 0.2, which is what we're looking for.

Hope this helps!

8 0
3 years ago
How does the work required to accelerate a particle from 10m/s to 20m/s compare to that required to accelerate it from 20m/s to
Stella [2.4K]

The answer is B. It is the same..... hope this helps!

7 0
3 years ago
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