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ss7ja [257]
3 years ago
13

How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?

Physics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

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Force between two charges is given by

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F =\frac{9*10^9* 1* 10^{-6}* 1 * 10^{-6}}{4^2}

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Two point charges of +2.50 x 10^-5 C and -2.50 x 10^-5 C are separated by 0.50m. Which of the following describes the force betw
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Answer:

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Using Coulomb's law:

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F= 5.625/ 0.25

F= 22.5N approximately

F= 23N.

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3 years ago
On my bike I was able to travel 40 miles in one hour from this information we can determine the bikes
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3 years ago
The three components of velocity in a velocity field are given by u = Ax + By + Cz, v = Dx + Ey + Fz, and w = Gx + Hy + Jz. Dete
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Answer:

The relationship is only between the coefficients A, E and J which is:

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Explanation:

Given:

The three components of velocity is a velocity field are given as:

u = Ax + By + Cz\\\\v = Dx + Ey + Fz\\\\w = Gx + Hy + Jz

The fluid is incompressible.

We know that, for an incompressible fluid flow, the sum of the partial derivatives of each component relative to its direction is always 0. Therefore,

\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z}=0

Now, let us find the partial derivative of each component.

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Hence, the relationship between the coefficients is:

A+E+J=0

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The answer is conductor

Explanation:

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