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ss7ja [257]
3 years ago
13

How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?

Physics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

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Read 2 more answers
In a 400-m relay race the anchorman (the person who runs the last 100 m) for team A can run 100 m in 9.8 s. His rival, the ancho
melisa1 [442]

Answer:

largest lead = 3 m

Explanation:

Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.

So, first we need to calculate the velocities of both the anchorman  

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Time arrival for B = 10.1 s

Velocity of anchorman A = D / Time arrival for A

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Velocity of anchorman B = D / Time arrival for B

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So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.

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So if his lead no more than 3 m anchorman A win the race.

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