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4 years ago

If arranged in order of increasing atomic mass, which element would come after chlorine?

Chemistry

2 answers:

SashulF [63]4 years ago

7 0

Answer;

Potassium

Explanation;

The Russian chemist Dmitri Mendeleev was the first scientist to make a periodic table similar to the one used today. Mendeleev arranged the elements by atomic mass, corresponding to relative molar mass.

When the elements are arranged in order of increasing atomic mass, certain sets of properties recur periodically;

In this case; P- 31. S- 32, Cl-35 , K-39, Ca- 40 and so forth.

Eva8 [605]4 years ago

3 0

Look at the periodic table the element next at the right of Cl is the Ar and the atomic mass is 39.948 is bigger than the Cl 35.45. All the elements after that has mases bigger than Cl.

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Answer:six tryangles to four circle

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3 years ago

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Here's the question ~

Lelechka [254]

Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.

Using the Rydberg formula;

1/λ = RH(1/nf^2 - 1/ni^2)

Given that;

λ = wavelength

RH = Rydberg constant

nf = final state

ni = initial state

When final state = 3 and initial state = ∞

Then;

1/λ = 1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)

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Learn more about the Rydberg formula; brainly.com/question/17753747

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3 years ago

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Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The

yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of $N_2$ = 8.00 atm

The partial pressure of $O_2$ = 5.00 atm

$K_p$ = 0.0025

The balanced equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initial pressure 8.00 5.00 0

At eqm. (8.00-x) (5.00-x) 2x

The expression of equilibrium constant $K_p$ for the reaction will be:

$K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}$

Now put all the values in this expression, we get :

$0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}$

By solving the terms, we get:

$x=0.15atm$

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4 years ago

Sally adds 3.13 moles of argon to a 5.29 liter balloon that already contained 4.21 moles of argonWhat is the volume of the ballo

lara31 [8.8K]

11.89, I hope this helped:)

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3 years ago

Suppose a current of flows through a copper wire for seconds. Calculate how many moles of electrons travel through the wire. Be

vagabundo [1.1K]

Answer:

1.20 × 10⁻³ mol e⁻

Explanation:

There is some info missing. I think this is the original question.

Suppose a current of 0.880 A flows through a copper wire for 132 seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.

Step 1: Given data

Intensity of the current (I): 0.880 A (= 0.880 C/s)

Time elapsed (t): 132 s

Step 2: Calculate the charge, in Coulomb, that travel through the wire

We will find the circulating charge (q) using the following expression.

$q = I \times t = \frac{0.880C}{s} \times 132s = 116C$

Step 3: Calculate the moles of electrons with a charge of 116 C

We will use the relationship 1 mole of electrons = 96,486 C (Faraday's constant)

$116C \times \frac{1mol\ e^{-} }{96,486 C} =1.20 \times 10^{-3} mol\ e^{-}$

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3 years ago