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SVEN [57.7K]
3 years ago
14

Moles in 9.8g of calcium

Chemistry
1 answer:
Nataly [62]3 years ago
8 0
(9.8/1) x 1mol/40g = 0.245 mol
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Calculate (a) the number of moles of hydrogen required to react with 0.0969 moles of nitrogen, and (b) the number of moles of am
Bumek [7]

Answer:

The answer to your question is:

Explanation:

Data

moles H=?

moles of N = 0.0969

moles of NH₃=?

                            N₂ (g)  + 3 H₂ (g)  ⇒   2NH₃ (g)

Process

1.- Set a rule of three to calculate the moles of hydrogen

                         1 mol of nitrogen  -------------   3 moles of hydrogen

                         0.0969 moles of N ----------     x

                         x = (0.0969 x 3) / 1

                         x = 0.2907 moles of hydrogen          

2.- Set a rule of three to calculate the moles of ammonia

                        1 mol of nitrogen --------------  2 moles of ammonia

                        0.0969 mol of N --------------   x

                        x = (0.0969 x 2) / 1

                        x = 0.1938 moles of ammonia                

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