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3 years ago

10. If one body is positively charged and another body is negatively charged, free electrons tend to

Physics

1 answer:

marta [7]3 years ago

7 0

Answer: B.move from the negatively charged body to the positively charged body.

Explanation: If one body is positively charged and another body is negatively charged, free electrons tend to move from the negatively charged body to the positively charged body. This happens because they have different charges and therefore electrons are more attracted to the positive or its opposite charge.

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Why isn't iron used to make coin

AleksandrR [38]

If iron were used to make coins then it would rust easily,because of its exposure to water, air etc..

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3 years ago

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If the average frequency emitted by a 160 W light bulb is 5.00 1014Hz and 10.0 of the input power is emitted as visible light ap

bearhunter [10]

Answer:

The value is $\frac{n}{t} = 4.83 *10^{19} \ photons / s$

Explanation:

From the question we are told that

The power rating of the bulb is $P = 160 \ W$

The frequency is $f = 5.00 *10^{14} \ Hz$

The percentage of the input power that is emitted as visible light is $\eta = 10\% = 0.10$

Generally the amount of power emitted as visible light is mathematically represented as

$P_l = 0.10 * P_i$

=> $P_l = 0.10 *160$

=> $P_l = 16 \ W$

Generally the amount of energy emitted as light is mathematically represented as

$E = n * h * f$

Here n is the number of photon , h is the Planks constant with value $h = 6.625*10^{-34} \ J\cdot s$

Generally this power emitted as visible light is mathematically represented as

$P_l = \frac{E}{t}$

=> $P_l = \frac{E}{t} = \frac{nhf}{t}$

=> $\frac{n}{t} = \frac{P_l }{hf}$

=> $\frac{n}{t} = \frac{16 }{6.625 *10^{-34}* (5.00*10^{14})}$

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3 years ago

A circular loop of wire with 15 turns, radius 0.129 m and resistance 0.251 Ohms is connected to a 16.7 V power supply. The magne

Licemer1 [7]

The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.

<h3>Current in the wire</h3>

The current in the wire is calculated as follows;

V = IR

I = V/R

I = 16.7/0.251

I = 66.53 A

<h3>Magnetic field at the center of the loop</h3>

The magnetic field at the center of the circular loop is calculated as follows;

$B = \frac{\mu_0 I}{2R} \\\\B = \frac{4\pi \times 10^{-7} \times66.53 }{2\times 0.129} \\\\B = 3.24 \times 10^{-4} \ T$

Learn more about magnetic field here: brainly.com/question/7802337

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2 years ago

A wire is stretched 30% what is the percent age change in resistance?

IgorC [24]

The Resistance is directly proportional to conductor length. Therefore 30% increase in wire length will increase the resistance by 30%.

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3 years ago

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tensa zangetsu [6.8K]

Answer:

Explanation:

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4 years ago

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