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Sedbober [7]
4 years ago
9

How does latitude affect climate?

Physics
2 answers:
kicyunya [14]4 years ago
8 0

Answer:

The CORRECT ANSWER is Latitude determines the duration of daylight hours on E2020

Alex73 [517]4 years ago
3 0
<h3><u>Answer;</u></h3>

Latitude determines the duration of daylight hours.

<h3><u>Explanation;</u></h3>
  • <em><u>The amount of daylight hours depends on the latitude and how Earth orbits the sun. </u></em>
  • <em><u>The tilting of the earth  as it orbits the sun leads to a variation of solar energy that changes with latitude which causes a seasonal variation in the intensity of sunlight reaching the surface and the number of hours of daylight.</u></em>
  • Daylight hours are shortest in each hemisphere's winter. Between summer and winter solstice, the number of daylight hours decreases, and the rate of decrease is larger the higher the latitude.
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Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52
krek1111 [17]

Answer:

t = 1.31 s

Explanation:

Given that,

The top of a roof is located 8.52  meters above the ground.

We need to find the time required for the shingles to reach  the ground. Let the time be t. Its initial velocity was 0 as it was at rest initially. Using the equation of motion to find it as follows :

s=ut+\dfrac{1}{2}gt^2

Where

t is the time and u = 0

s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 8.52}{9.8}} \\\\t=1.31\ s

So, it will take 1.31 seconds for the shingles to reach the ground.

5 0
3 years ago
It has been proposed that a spaceship might be propelled in the solar system by radiation pressure, using a large sail made of f
Anestetic [448]

Answer:

A = 8.34 x 10^(5) m²

Explanation:

The intensity of the solar radiation is the average solar power per unit area. Thus,

I = P/4A = P/(4(πr²))

Where;

P is average solar power.

r is it's distance from centre of sun

A is area

Now, The rate at which the Sun emits energy has a standard value of 3.90 × 10^(26) W

Thus;

I = [3.90 × 10^(26)]/(4πr²)

I = [3 x 10^(25)]/r²

Now, the formula for radiation pressure is;

P_rad = 2I/c

Where c is speed of light and has a value of 3 x 10^(8) m/s

Thus,

P_rad = 2([3 x 10^(25)]/r²)/(3 x 10^(8))

P_rad = [2.07 x 10^(17)]/r² N/m²

Also, Radiation pressure on ship; P_rad = F/A

Where Force on ship and A is area.

Thus;

F = P_rad x A

So, F = [2.07 x 10^(17)•A]/r²

Now,

F_grav = GMm/r²

Where;

G is gravitational constant with a value = 6.67 x 10^(-11) Nm²/kg²

M is mass of sun with a value of 1.99 x 10^(30)

m is mass of ship and sail = 1300 kg

Thus, plugging in the relevant values to obtain;

F_grav = (6.67×10^(-11) × 1.99 x 10^(30) × 1300)/r²

F_grav = [17.255 x 10^(22)]/r²

Now, equating F to F_grav, we get;

[2.07 x 10^(17)•A]/r² = [17.255 x 10^(22)]/r²

r² will cancel out to give;

2.07 x 10^(17)•A= [17.255 x 10^(22)]

A = [17.255 x 10^(22)]/2.07 x 10^(17)

A = 8.34 x 10^(5) m²

7 0
4 years ago
A 1500 kg car is moving 18 m/s how much force is required to bring the car to a stop in 12 seconds
Marat540 [252]

Answer:

2250N

Explanation:

F = Mv/t

Force F =?

Mass M = 1500kg

Velocity v = 18m/s

Time T = 12 secs

Therefore

F = 1500 x 18 /12

Multiply through

F = 27000/12

F = 2250N

3 0
3 years ago
A 500 kg crate is lifted by a crane and accelerated upward at 2 m/s/s. What is the tension force in the cable pulling up on the
Likurg_2 [28]
Answer = 1000N
F = ma
M = 500kg
a= 2 m/s/s
Solve for F
6 0
3 years ago
On what factors, current sensitivity voltage sensitivity of<br>a galvanometer depend?​
Eddi Din [679]

Answer:

Current sensitivity voltage sensitivity of a galvanometer depend is on a number of turns, coil area, restoring force per unit twist and megnetic filed.

7 0
3 years ago
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