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4 years ago

How does latitude affect climate?

Physics

2 answers:

kicyunya [14]4 years ago

8 0

Answer:

The CORRECT ANSWER is Latitude determines the duration of daylight hours on E2020

Alex73 [517]4 years ago

3 0

<h3><u>Answer;</u></h3>

Latitude determines the duration of daylight hours.

<h3><u>Explanation;</u></h3>

<em><u>The amount of daylight hours depends on the latitude and how Earth orbits the sun. </u></em>
<em><u>The tilting of the earth as it orbits the sun leads to a variation of solar energy that changes with latitude which causes a seasonal variation in the intensity of sunlight reaching the surface and the number of hours of daylight.</u></em>
Daylight hours are shortest in each hemisphere's winter. Between summer and winter solstice, the number of daylight hours decreases, and the rate of decrease is larger the higher the latitude.

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A 0.086 kg bullet is fired at 266 m/s and collides with a 6.3 kg wooden block that is initially stationary. The bullet embeds in

olga2289 [7]

Answer:

The value of speed of wooden block at the instant after the collision $V_f =$ 262.41 $\frac{m}{s}$

Explanation:

Given data

Mass of block = 6.3 kg

Mass of bullet = 0.086 kg

Velocity of bullet $V_0$ = 266 $\frac{m}{s}$

Final velocity of whole system is

$V_f = M_{b}\frac{ V_0}{M_b + (M_{block})}$

Put all the values in above formula we get

$V_f = \frac{(6.3)(266)}{(6.3 + 0.086)}$

$V_f =$ 262.41 $\frac{m}{s}$

This is the value of speed of wooden block at the instant after the collision.

7 0

3 years ago

For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is

ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀ $e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)$

where A(t)=A₀ $e^{\frac{-bt}{2m}}$

A₀ is the amplitude at t=0 and

$w'$ is the angular frequency of damped SHM, which is given by,

$w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

Now coming to the problem,

Given: m=1.2 kg

k=9.8 N/m

b=210 g/s= 0.21 kg/s

A₀=13 cm

a) A(t)=A₀/8

⇒A₀ $e^{\frac{-bt}{2m}}$ =A₀/8

⇒ $e^{\frac{bt}{2m}}=8$

applying logarithm on both sides

⇒ $\frac{bt}{2m}=ln(8)$

⇒ $t=\frac{2m*ln(8)}{b}$

substituting the values

$t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)$

b) $w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

$w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}$

$T'=\frac{2\pi}{w'}$ , where $T'$ is time period of damped SHM

⇒ $T'=\frac{2\pi}{2.86}=2.2s$

let $n$ be number of oscillations made

then, $nT'=t$

⇒ $n=\frac{24}{2.2}=11(approx)$

8 0

4 years ago

What keeps the hydrogen atoms together in the molecule ?

blagie [28]

The bonds that hold atoms together to form molecules are called covalent bonds. They are pretty tough and not easily made or broken apart. It takes energy to make the bonds and energy is released when the bonds are broken.

7 0

3 years ago

The surface temperature of a planet depends on both the distance of the planet from the Sun and on how the panet's atmosphere di

BaLLatris [955]

Answer:

Aphelion: 6404 W/m2

Perihelion: 14978 W/m2

Explanation:

The solar energy flux depends on the solar power output divided by the surface of a sphere with a radius equal to the distance to the Sun.

$\Phi sol = \frac{Psol}{4 * \pi * d^2}$

The distances we need are the aphelion and perihelion of Mercury.

Planetary orbits are ellipses. In an ellipse the eccentricity is related to linear eccentricity and the length of the semi major axis:

$e = \frac{c}{a}$

Where

e: eccentricity

c: linear eccentricity

a: semi major axis

The linear eccentricity is equal to the distance of the focus of the center of the ellipse.

$c = a * c =$

a = 0.39 AU = 5.83e10 m

$c = 5.83e10e * 0.21 = 1.22e10 m$

In planetary orbits the Sun is in one of the fucuses. With this we can calculate the prihelion and aphelion as:

Ap = a + c = 5.83e10 + 1.22e10 = 7.05e10 m

Pe = a - c = 5.83e10 - 1.22e10 = 4.61e10 m

And the solar energy fluxes will be:

$\Phi Ap = \frac{4e26}{4 * \pi * 7.05e10^2} = 6404 W/m2$

$\Phi Pe = \frac{4e26}{4 * \pi * 4.61e10^2} = 14978 W/m2$

4 0

3 years ago

A sound wave traveling downward with a speed of about 4,000 m/s suddenly slows to 1,500 m/s not far below the Earth’s surface. W

mezya [45]

<h2>Answer: an underground lake</h2>

Explanation:

In general, sound (mechanical waves) travels faster in solids than in liquids, and faster in liquids than in gases. This is because <u>the speed of the mechanical waves is determined by a relationship between the elastic properties of the medium </u>in which they are propagated and the mass per unit volume of the medium (that is:<u>density</u>).

In other words: The speed of sound varies depending on the medium through which the sound waves travel.

So, if we are told the sound wave initially had a speed of 4,000 m/s and it suddenly decreases to 1,500 m/s, this means the sound waves passed from a solid medium to a liquid medium.

Hence, the correct option is: an underground lake.

8 0

4 years ago

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