Answer:
learning about the different functions of the body and therefore they have enough practice in order to have a clean and safe operation
Explanation:
Complete Question
A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.
What is the refrigerator's coefficient of performance? COP
(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP
Answer:
a

b
Explanation:
From the question we are told that
The lower operation temperature of refrigerator is
The upper operation temperature of the refrigerator is 
Generally the refrigerators coefficient of performance is mathematically represented as

=> 
=> 
Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as
=>
=>
<span>3.2x10^-2 seconds (0.032 seconds)
This is a simple matter of division. I also suspect it's an exercise in scientific notation, so here is how you divide in scientific notation:
9.6 x 10^6 m / 3x10^8 m/s
First, divide the significands like you would normally.
9.6 / 3 = 3.2
And subtract the exponent. So
6 - 8 = -2
So the answer is 3.2 x 10^-2
And since the significand is less than 10 and at least 1, we don't need to normalize it.
So it takes 3.2x10^-2 seconds for the radio signal to reach the satellite.</span>