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likoan [24]
2 years ago
9

Two liquids are in a graduated cylinder - Liquid A has a density of 1.004 g/cm3 and Liquid B has a density of 0.6223 g/cm3 . Ass

uming that they do NOT mix, which liquid is on top and which liquid is on bottom? Where would you expect to find the plastic cube from Question #2 if it is dropped into the graduated cylinder with these two liquids?
Chemistry
1 answer:
MatroZZZ [7]2 years ago
6 0

Answer: water is the stuff

Explanation: dont judge me alex

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You measure 2.34 g of K2Cr2O7 into a volumetric flask. You dilute the K2Cr2O7 with water to a volume of 250 mL. It takes 35.7 mL
natta225 [31]

Answer:

0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution

Explanation:

The reaction of potassium dichromate, K₂Cr₂O₇ with sodium oxalate, Na₂C₂O₄ in the presence of acid H⁺ is:

K₂Cr₂O₇ + 3Na₂C₂O₄ + 14H⁺ → 2Cr³⁺ + 6CO₂ + 7H₂O + 6Na⁺ + 2K⁺

<em>Thus, 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄</em>

Moles of 2.34g of K₂Cr₂O₇ (Molar mass: 294.185g/mol):

2.34g K₂Cr₂O₇ ₓ (1mol / 294.185g) = 7.954x10⁻³ moles K₂Cr₂O₇

In 250mL = 0.250L:

7.954x10⁻³ moles K₂Cr₂O₇ / 0.250L = 0.0318M K₂Cr₂O₇

Moles in 35.7mL = 0.0357L of this solution are:

0.0357L ₓ (0.0318mol / L) = <em>1.136x10⁻³ moles K₂Cr₂O</em>₇ in solution. As 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄, to titrate the moles of K₂Cr₂O₇ in solution you need:

1.136x10⁻³ moles K₂Cr₂O₇ × (3 moles Na₂C₂O₄ / 1 mole K₂Cr₂O₇) =

<em>3.408x10⁻³ moles of Na₂C₂O₄</em>

In 17.8mL = 0.0178L:

3.408x10⁻³ moles of Na₂C₂O₄ / 0.0178L =

<h3>0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution</h3>

<em />

3 0
3 years ago
6. How does decomposition factor into the quality of soil? )
USPshnik [31]

Answer:

Explanation:

The fertility of soil is improved decomposition.

3 0
3 years ago
What observation did Rutherford make from his gold-foil experiment which
JulsSmile [24]

Answer:

A piece of gold foil was hit with alpha particles, which have a positive charge. Most alpha particles went right through. This showed that the gold atoms were mostly empty space. Some particles had their paths bent at large angles. A few even bounced backward. The only way this would happen was if the atom had a small, heavy region of positive charge inside it.

8 0
3 years ago
List the following aqueous solutions in order of increasing boiling point: 0.12 m C6H12O6, 0.05 m LiBr, and 0.05 m Zn(NO3)2. Exp
GalinKa [24]

<u>Answer:</u> The order of increasing boiling points follows:

\text{LiBr }

<u>Explanation:</u>

The expression of elevation in boiling point is given as:

\Delta T_b=i\times k_b\times m

where,

\Delta T_b = Elevation in boiling point

i = Van't Hoff factor  

T_b = change in boiling point

k_b = boiling point constant

m = molality

For the given options:

  • <u>Option 1:</u>  0.12 m C_6H_{12}O_6

Value of i = 1   (for non-electrolytes)

So, molal concentration will be = (0.12)\times 1=0.12m

  • <u>Option 2:</u>  0.02 m LiBr

Value of i = 2

So, molal concentration will be = (0.02)\times 2=0.04m

  • <u>Option 3:</u>  0.05 m Zn(NO_3)_2

Value of i = 3

So, molal concentration will be = (0.05)\times 3=0.15m

As, the molal concentration of Zn(NO_3)_2 is the highest, so its boiling point will be the highest.

Hence, the order of increasing boiling points follows:

\text{LiBr }

8 0
3 years ago
Question 7 of 32
Sever21 [200]

Answer:O D to protect the environment from harmful chemicals

Explanation:

3 0
4 years ago
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