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yuradex [85]
3 years ago
7

What is the law of conservation of mass? How it is related to balancing chemical equations

Chemistry
2 answers:
siniylev [52]3 years ago
8 0
The law of conservation of mass states that whatever goes in comes out the same. That's not the exact concept, but it'll help you remember it.

Here's another way of thinking about it.

Okay, so, we have:

Reactants  ⇒ Products

The reactants form into products, but stay the same.

What does this mean?

This means that the mass is conserved. When mass is conserved, the energy is also conserved.

In other words, nothing has changed.

Now, lets relate that to balancing equations.

When you try to balance an equation, what is your goal? ⇒ To get the reactants to equal the products..? Right?

Ah, yes!

Now we have the exact meaning→→→→

The law of conservation of mass states that mass is always conserved in a chemical reaction.

Hope I helped! Please feel free to comment with questions! :)
Katarina [22]3 years ago
8 0
Law that states that mass is neither created or destroyed in ordinary chemical and physical changes.
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Consider the insoluble compound silver bromide , AgBr . The silver ion also forms a complex with ammonia . Write a balanced net
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Answer:

- AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)

- K=1.2x10^{-5}

Explanation:

Hello,

In this case, by considering the dissolution of silver bromide:

AgBr(s)\rightleftharpoons Ag^+(aq)+Br^-(aq) \ \ \ Ksp=[Ag^+][Br^-]=7.7x10^{-13}

And the formation of the complex:

Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)\ \ \ Kf=\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}=1.6x10^7

We obtain the balanced net ionic equation by adding the aforementioned equations:

AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)+Ag^+(aq)\\\\AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)

Now, the equilibrium constant is obtained by writing the law of mass action for the non-simplified net ionic equation:

AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-+Ag^+\\\\K=[Ag^+][Br^-]*\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}

So we notice that the equilibrium constant contains the solubility constant and formation constant for the initial reactions:

K=Ksp*Kf=7.7x10^{-13}*1.6x10^{7}\\\\K=1.2x10^{-5}

Best regards.

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