Answer:
- 
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Explanation:
Hello,
In this case, by considering the dissolution of silver bromide:
![AgBr(s)\rightleftharpoons Ag^+(aq)+Br^-(aq) \ \ \ Ksp=[Ag^+][Br^-]=7.7x10^{-13}](https://tex.z-dn.net/?f=AgBr%28s%29%5Crightleftharpoons%20Ag%5E%2B%28aq%29%2BBr%5E-%28aq%29%20%5C%20%5C%20%5C%20Ksp%3D%5BAg%5E%2B%5D%5BBr%5E-%5D%3D7.7x10%5E%7B-13%7D)
And the formation of the complex:
![Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)\ \ \ Kf=\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}=1.6x10^7](https://tex.z-dn.net/?f=Ag%5E%2B%28aq%29%2B2NH_3%28aq%29%5Crightleftharpoons%20Ag%28NH_3%29_2%5E%2B%28aq%29%5C%20%5C%20%5C%20Kf%3D%5Cfrac%7B%5BAg%28NH_3%29_2%5E%2B%5D%7D%7B%5BAg%5E%2B%5D%5BNH_3%5D%5E2%7D%3D1.6x10%5E7)
We obtain the balanced net ionic equation by adding the aforementioned equations:

Now, the equilibrium constant is obtained by writing the law of mass action for the non-simplified net ionic equation:
![AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-+Ag^+\\\\K=[Ag^+][Br^-]*\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}](https://tex.z-dn.net/?f=AgBr%28s%29%2BAg%5E%2B%28aq%29%2B2NH_3%28aq%29%5Crightleftharpoons%20Ag%28NH_3%29_2%5E%2B%28aq%29%2BBr%5E-%2BAg%5E%2B%5C%5C%5C%5CK%3D%5BAg%5E%2B%5D%5BBr%5E-%5D%2A%5Cfrac%7B%5BAg%28NH_3%29_2%5E%2B%5D%7D%7B%5BAg%5E%2B%5D%5BNH_3%5D%5E2%7D)
So we notice that the equilibrium constant contains the solubility constant and formation constant for the initial reactions:

Best regards.
Light<span> transfers energy, and if this energy is absorbed it </span>will<span> heat the </span>food<span>. So yes visible lights do.</span>
Answer:
Explanation:
1 is true
2 is false
3 is true
4 is true
5 is false
That is what I got from researching.
Answer: A and C
Explanation:
It would even out the number of particles per section