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insens350 [35]
3 years ago
10

What observation did Rutherford make from his gold-foil experiment which

Chemistry
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

A piece of gold foil was hit with alpha particles, which have a positive charge. Most alpha particles went right through. This showed that the gold atoms were mostly empty space. Some particles had their paths bent at large angles. A few even bounced backward. The only way this would happen was if the atom had a small, heavy region of positive charge inside it.

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Which term labels a solution
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B. Homogenous mixture.
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Need help ASAP plz. Only gave 10 min
MrRissso [65]

Answer:

the answer is D

Explanation:

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Lab report for physical and chemical changes??!
slega [8]

Answer:

[See Below]

Explanation:

✦ Physical Changes:

  ✧ Is when the form changes, but not the chemicals in that form.

  ✧ An example of this would be chopping wood. It's still wood but it's a different size now. It's easier to burn it since it's smaller.

✦ Chemical Changes:

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~<em>Hope this helps Mate. If you need anything feel free to message me.</em>

7 0
3 years ago
7. A figure skater skating across ice, who grabs another skater and brings him along the ice with her, is an example of what typ
xenn [34]

Answer:

The type of collision is A. Inelastic collision.

Explanation:

The macroscopic collisions are generally inelastic and do not conserve the kinetic energy, although of course the total energy is conserved. The inelastic collision is one in which the objects that collide remain together after the collision.

So, a figure skater skating across ice, who grabs another skater and brings him along the ice with her is a clear example of inelastic collision.

6 0
3 years ago
Read 2 more answers
You’re going on a plane from Alaska to Florida and you’re taking your bike. It’s the middle of the winter. You fill up your tire
12345 [234]

Answer:

5.52atm

Explanation:

Using the pressure law formula:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question, the following information were provided;

P1 = 4.72 atm

P2 = ?

T1 = -3.50°C = -3.50 + 273 = 269.5K

T2 = 42°C = 42 + 273 = 315K

Using P1/T1 = P2/T2

4.72/269.5 = P2/315

CROSS MULTIPLY

4.72 × 315 = 269.5 × P2

1,486.8 = 269.5P2

P2 = 1,486.8 ÷ 269.5

P2 = 5.52atm

8 0
3 years ago
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