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insens350 [35]
2 years ago
10

What observation did Rutherford make from his gold-foil experiment which

Chemistry
1 answer:
JulsSmile [24]2 years ago
8 0

Answer:

A piece of gold foil was hit with alpha particles, which have a positive charge. Most alpha particles went right through. This showed that the gold atoms were mostly empty space. Some particles had their paths bent at large angles. A few even bounced backward. The only way this would happen was if the atom had a small, heavy region of positive charge inside it.

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Calculate the percentage of yield when 20 grams of sodium chloride solution reacts with an excess amount of silver nitrate solut
Lady bird [3.3K]

%yield = 91.8

<h3>Further explanation</h3>

Given

20 g NaCl

45 g AgCl

Required

%yield

Solution

Reaction

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

mol NaCl :

= mass : MW

= 20 g : 58,44 g/mol

= 0.342

mol AgCl from equation :

= 1/1 x mol NaCl

= 1/1 x 0.342

= 0.342

Mass AgCl(theoretical) :

= mol x MW

= 0.342  x 143,32 g/mol

= 49.02 g

%yield = (actual/theoretical) x 100%

%yield = (45/49.02) x 100%

%yield = 91.8

7 0
2 years ago
How does a runoff get polluted.
azamat

Answer:

any litter on the ground can be swept up into the runoff. dirty ground water also commonly affects runoff since there are so many chemicals in the ground. farmers especially need to be cautious because teir fertilizers can leak into the ground.

5 0
3 years ago
Read 2 more answers
Calculate how many moles of silver nitrate (AgNO3) are in 1.35 L of a 4.25 M solution of silver
Svetach [21]

Answer:

is

Explanation:

is

3 0
3 years ago
How many significant figures are there in the measurement 0.0034 Kg?
Mama L [17]

Answer:

2 significant figures

Explanation:

Your measurement will have 2 significant figures, the two non-zero digits.

<em>I hope this helps you out! :)</em>

8 0
2 years ago
Read 2 more answers
How many joules of energy are made by the loss of 100kg of mass using the formula E=mc2? please help!!!
asambeis [7]

Answer:

E = 3 × 10¹⁰ J

Explanation:

Mass, m = 100 kg

We need to find energy made by the loss of 100 kg of mass. The formula between the mass and energy is given by :

E = mc²

Where c is speed of light

Putting all the values, we get :

E = 100 kg × (3×10⁸ m/s)²

= 3 × 10¹⁰ J

So, the required energy is 3 × 10¹⁰ J.

6 0
3 years ago
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