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Colt1911 [192]
2 years ago
9

What is the difference between renewable and non-renewable resources? (Select all that apply).

Mathematics
1 answer:
gtnhenbr [62]2 years ago
4 0

Answer:

non renewable you can't renew what you already bought and renewable you can renew what you bought

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8(x+2) Evaluate when x=3
Burka [1]

When the value of x is 3, evaluate;

8(x+2)

Substitute for the value of x into the parenthesis;

\begin{gathered} 8(x+2)=8(3+2) \\ 8(x+2)=8(5) \\ 8(x+2)=40 \end{gathered}

ANSWER:

The expression equals 40 (when x = 3)

6 0
1 year ago
Simplify 3(7-3) the second power -4(6+2)
expeople1 [14]

Answer:

112

Step-by-step explanation:

3(7-3) = 3 x 4 = 12

12^2 = 144

144 -4(6+2)

144-4(8)

144-32

112

8 0
3 years ago
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A family paid ​$30600 as a down payment for a home. If this represents ​%17 of the price of the​ home, find the price of the hom
snow_lady [41]

Answer:

180000

Step-by-step explanation:

30600/17=1800

1800•100=180000

7 0
3 years ago
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can someone please help me find the surface area of the pyramid with an equilateral triangle for a base
ioda

To obtain the total surface we have to calculate the surface of the 4 triangles and add up the areas (remember that the area of a triangle is (b*h)/2 , b is the base, h is the height ).

We will caculate first the area of the base triangle for that we considerer the fact that it is an equilateral triangle with sides of lenght 6 cm, now we calculate the height, I am going to draw please wait a moment

using the pythagorean theorem we have that

\begin{gathered} h^2=6^2cm^2-3^2\operatorname{cm}=27cm^2 \\ h=\text{ }\sqrt[]{27\text{ }}cm \end{gathered}

Then, the area of the triangle is 6*h/2 = 3h = 15.59 cm^2.

Now we calculate the area of the other 3 triangles, notice that those triangles have the same base and height so we will calculate for one of them and multiply by 3. From the image we know that the height is 15cm and the base is 6 cm so the area is 45cm^2, and 45*3 cm^2 = 135cm^2.

Finally we add up all the areas:

135cm^2+15.59cm^2=150.59cm^2

6 0
1 year ago
How do i solve 4m^2+3m-1=0 using the quadratic formula
elixir [45]
Quadratic formulat is used when a^2+bx+c=0 x= \frac{-b+/- \sqrt{b^{2}-4ac}   }{2a} 4m^2+3m-1=0 a=4 b=3 c=-1 input x= \frac{-3+/- \sqrt{3^{2}-4(4)(-1)}   }{2(4)} x= \frac{-3+/- \sqrt{9+16}   }{8} x= \frac{-3+/- \sqrt{25}   }{8} x= \frac{-3+/-5  }{8} x= \frac{-8}{8} or \frac{2}{8} x=-1 or 1/4
8 0
4 years ago
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