1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zielflug [23.3K]
2 years ago
13

Seth and Diana were asked to be the leaders for a game of tag during recess at school. Seth and Diana can ensure that all intere

sted students get a chance to participate equally regardless of ability to run fast by having the: Tagged players sit out until the next game starts Tagged players perform a fitness activity then return to the game Two youngest students be the taggers Two fastest students be the taggers
Physics
1 answer:
grandymaker [24]2 years ago
3 0

Answer:

B

Explanation:

did this yesterday with my friend

You might be interested in
A gyre is a set of currents that form:
tangare [24]
A gyre is a set of currents that form b. a loop. The circulation of gyres are affected by global wind patterns, landmasses, and the planet's rotation. The circulation is also affected by temperature, as warm water goes up and cold water sinks. There are five major gyres in the world: <span>North Atlantic, South Atlantic, Indian, North Pacific, and South Pacific.</span>
7 0
3 years ago
Read 2 more answers
An airplane was 300 km [N] of Toronto airport, 3 hours later the airplane 600 km [S]
Alecsey [184]

Answer:

Explanation:

a) 300 + 600 = 900 km S

b) 900/3 = 300 km/hr S

8 0
3 years ago
Aquatic ecosystems consist of two different layers with respect to light. The photic zone is where light penetrates the water, a
Lostsunrise [7]

Answer: a

Explanation: it talks about how they live without that much light

7 0
3 years ago
Read 2 more answers
Please need help on this
REY [17]
The handle of a metal pot gets warm when the water inside the pot starts to boil
8 0
3 years ago
Elect the correct answer. Two identical projectiles, A and B, are launched with the same initial velocity, but the angle of laun
allsm [11]

Answer:

A. The range of A and B are equal.

Explanation:

Let u be the initial speed of both the projectile.

The gravitational force acting in the projectile is in the downward direction, sp the speed of the projectile in the horizontal direction remains constant and equals to the initial horizontal speed.

For projectile, a projectile having initial velocity u at an angle \theta with the horizontal direction,

The speed in the horizontal direction = u\cos\theta

and the speed in the vertical direction is = u\sin\theta upward.

For A:

The speed in the horizontal direction = u\cos75^{\circ}

and the speed in the vertical direction is = u\sin75^{\circ} upward.

For B:

The speed in the horizontal direction = u\cos15^{\circ}

and the speed in the vertical direction is = u\sin15^{\circ} upward.

Let t_A and t_B are the time of flight for projectile A and B respectively.

As the range is the horizontal distance traveled by the projectile, so

The range for the projectile A = u\cos75^{\circ}\times t_A\cdots(i)

The range for the projectile B = u\cos15^{\circ}\times t_B\cdots(ii)

At the highest point, the vertical velocity is 0.

Bu using the equation of motion v^2=u^2 +2a s.

Here, the final velocity v=0, the initial velocity u = u \sin \theta , h= vertical distance up to the highest point, and a= -g (as per sign convention).

So, s= \frac{u^2\sin^2 \theta}{2g}

For projectile A: The maximum height attained.

s_A= \frac{u^2\sin^2 75^{\circ}}{2g}

For projectile B: The maximum height attained.

s_B= \frac{u^2\sin^2 15^{\circ}}{2g}

As \sin^2 75^{\circ} > \sin^2 15^{\circ}, the height of A is attained by A is more than the heigHt attained by B.

Now, the times required to reach the highest point from the ground and again form the highest point to the ground are the same.

So, the total time of flight = 2 x (Time to reach the highest point)

In a similar way, by using the equation of motion v=u+at,

The time to reach the highest point =\frac {u\sin\theta}{g}

where g is the acceleration due to gravity.

So, the total time of flight

= 2 \times \frac {u\sin\theta}{g}

The total time of flight for A

=2 \times \frac {u\sin75^{\circ}}{g}

The total time of flight for A

=2 \times \frac {u\sin15^{\circ}}{g}

Now, from equations (i) and (ii),

The range for the projectile A =

u\cos75^{\circ}\times  \frac {2u\sin75^{\circ}}{g}=\frac {u^2 \sin 150^{\circ}}{g}= \frac {u^2 \sin 30^{\circ}}{g}

The range for the projectile B =

u\cos15^{\circ}\times  \frac {2u\sin15^{\circ}}{g}=\frac {u^2 \sin 30^{\circ}}{g}.

Both the projectile have the same range.

Hence, option (A) is correct.

7 0
3 years ago
Other questions:
  • An object with an acceleration of –10 m/s² is _____.
    11·1 answer
  • Volume or intensity of a sound wave is measured by the size of the _________ and reported in decibels. A) amplitude B) frequency
    7·2 answers
  • Where do consumers get their nitrogen from?
    12·1 answer
  • Three identical train cars, coupled together, are rolling east at speed v0. A fourth car traveling east at 2v0 catches up with t
    13·1 answer
  • What movements of water has the greatest effect on the growth of producers
    8·1 answer
  • Light travels _____________ in a material with a higher index of refraction.
    8·2 answers
  • What type of energy depends upon an object mass and the object speed?
    8·1 answer
  • Please help, thank you to anyone who answers! Will mark brainliest, give a thanks and a 5 star.
    12·1 answer
  • If the ball is 0.60 mm from her shoulder, what is the tangential acceleration of the ball? This is the key quantity here--it's a
    6·1 answer
  • Why can't humans breathe in space?​
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!