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3 years ago

Once a scientist has made a hypothesis, what would they typically do next? (2 points)

Physics

1 answer:

ipn [44]3 years ago

4 0

Answer:

b-testing

Explanation:

First would be observation/research. Then the hypothesis. After that you would test your theory, conduct experiments. And finally, your conclusion- what you got from the whole process basically.

Hope this helps.

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Which characteristic must a food have to receive a “natural” label from the FDA ?

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No artificial ingredients
i only know that because my mom was vegan for two years

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3 years ago

A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to

goblinko [34]

Oh my lord lol I was do ready to help then I saw numbers

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3 years ago

Physical quantity are measurable quantities

Vilka [71]

Answer:

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7 0

2 years ago

Una pelota de béisbol de 142g de masa, luego de ser arrojada por el pitcher lleva una velocidad de 90mph. Luego de ser bateada s

V125BC [204]

Answer:

a) I = 13.38 kg m / s, b) F = 1,373 10³ N

Explanation:

The impulse is given by the relation

I = ∫ F dt = Δp

I = p_f -p₀

I = m (v_f - v₀)

take the ball's exit direction as positive, whereby the ball velocities

v₀ = -90mph, the final velocity v_f = + 54 m / s

Let's reduce the units to

I = 0.142 [54- (-40.23) ]

the SI system

v₀ = - 90 mph (1609.34 m / 1 mile) (1h / 3600 s = -40.23 m / s

m = 142 g (1kg / 1000) = 0.142 kg

we calculate

I = 0.142 [54- (-40) ]

I = 13.38 kg m / s

b) let's use the definition of momentum

I = ∫ F .dt

I = F ∫ dt

F = I / t

F = 13.38 / 0.008

F = 1,373 10³ N

5 0

3 years ago

A small artery has a length of 1.10 × 10-3 m and a radius of 2.50 × 10-5 m. If the pressure drop across the artery is 1.15 kPa,

levacccp [35]

Answer:

$7.69533\times 10^{-11}\ m^3/s$

Explanation:

P = Pressure difference = 1.15 kPa

r = Radius = $2.5\times 10^{-5}\ m$

$\eta$ = Viscosity of liquid = $2.084\times 10^{-3}\ Pas$

l = Length of artery = $1.1\times 10^{-3}\ m$

From Poiseuille's equation we have

$Q=\frac{\pi Pr^4}{8\eta l}\\\Rightarrow Q=\frac{\pi 1.15\times 10^3\times (2.5\times 10^{-5})^4}{8\times 2.084\times 10^{-3}\times 1.1\times 10^{-3}}\\\Rightarrow Q=7.69533\times 10^{-11}\ m^3/s$

The flow rate of blood is $7.69533\times 10^{-11}\ m^3/s$

8 0

2 years ago