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Ket [755]
3 years ago
13

If cos theta=-3/5 in quadrant 2 what is sin theta? A:4/5 B:3/4 C:-3/4 D:-4/5

Mathematics
1 answer:
Scrat [10]3 years ago
8 0
Answer: Choice A) 4/5

-------------------------------------------

Work Shown:

cos^2(theta) + sin^2(theta) = 1
(-3/5)^2 + sin^2(theta) = 1
9/25 + sin^2(theta) = 1
9/25 + sin^2(theta) - 9/25 = 1 - 9/25
sin^2(theta) = 1 - 9/25
sin^2(theta) = 25/25 - 9/25
sin^2(theta) = (25 - 9)/25
sin^2(theta) = 16/25
sqrt[sin^2(theta)] = sqrt[16/25]
sin(theta) = 4/5

The fact that sine is positive in quadrant 2 means that the result is positive.
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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question.
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Answer:

(a) Mean = 42.64

(b) Median= 37

(d)Midrange =39

Step-by-step explanation:

Given data,

60,31,19,55,21,37,94,62,41,15,34

(a)

Mean: Mean is the ratio of all observation to the total number of observation.

Mean=\frac{\textrn{sum of all observation}}{\textrm{Total number of observation}}

         =\frac{60+31+19+55+21+37+94+62+41+15+34}{11}

        =42.64

(b)

To find the mean of given data,first we have to arrange the date in ascending order or descending order.

Median: Median is middle term of the observation.

15,19,21,31,34,37,41,55,60,62,94

Median =(\frac{n+1}{2})^{th} term     n = Total number of observation=11

              =(\frac{11+1}{2})^{th}term

              = 6th term

              =37

(c)

Mode is a observation which repeat maximum time.

Here all observations have only one one frequency, so it is multimodel data.

(d)

Midrange: The substraction of first quartile from third quartile.

First quartile: The mid-value of lower half.

Lower portion :15,19,21,31,34

Q_1=21

Third quartile: The middle value of upper half.

upper half: 41,55,60,62,94

Q_3= 60

Mid range = Q_3-Q_1

                 =60-21

                 =39

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