Haha ironically I had this problem not too long ago, I hope by this we will both be better students. Everyone just needs practice. Ok stop to pep talk and lets go. I'll try to go step by step.
<span>So basically since this is a balanced equation, the ratios of mols of the elements are equal, atom wise. </span>
<span>So you notice they give you Br2 is 1.0 kg (1000g) and that means there are 2 mols of Br2. And its asking for Cl2, (on the left) it also has 2 mols. </span>
<span>Then you can start from 1000g Br2 and multiply with 2 mol Br2 and 159.8g Br2 on the bottom. The 159 8 is the actual grams per mol. Then when you write this down, continue multipying with the next fraction. </span>
<span>Since you know the molar mass of Cl2 is 70.4 and you know theres 2 mols, you can say that 2 mols of Br2 = 2 mols of Cl2 so you should be able to multiple 2 mol Br2 / 159.8g Br2 with 70.4 g Cl2 / 2 mol Cl2. Bam the mols cancel out and you have the grams for Cl2. Multiple all that out and you should get 443g Cl2. Notice how the beginning question gives 2 significant figures, so technically 440g Cl2 is more of an exact number.</span>
Answer:
TiCl2
Explanation:
Mass of the chloride of titanium= 1.31 g
Mass of titanium= 0.528 g
Therefore mass of chlorine = 1.31-0.528 = 0.782 g
To determine the empirical formulae of the titanium chloride, divide the mass of each element by its relative atomic mass and divide through by the lowest ratio.
Ti- 0.528/48 = 0.011, Cl- 0.782/35.5 = 0.022
Ti- 0.011/0.011 , Cl- 0.022/0.011
Ti- 1, Cl-2
Hence the required empirical formula is TiCl2
Answer:
Hydrogen and Oxygen
Explanation:
also it can be written as H2O
Explanation:
this is the answer of your question .
hope it helped you
