Answer:
A. 2.3 L
B. 6.10 L
C. 0.060 L
Explanation:
The question asks the volume of a 0.200 M solution of ethanol that contains certain number of moles of ethanol.
The M in the 0.200 M stands for Molarity. This is a unit of concentration that can be expressed as:
Molarity = moles of solute / Liters of solution
In this case:
0.200 M = moles of ethanol / Liters of solution
So from the formula we can get that we can calculate the volume of the solution, as Liters of solution, given the moles in each case as:
Liters of solution = moles of ethanol / 0.200 moles/L
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A. <u>0.45 mol ethanol</u>
Liters of solution = 0.45 moles / 0.200 moles/L = 2.25 L = 2.3 L
B. <u>1.22 mol ethanol</u>
Liters of solution = 1.22 moles / 0.200 moles/L = 6.10 L
C.<u> </u><u>1.2 x 10⁻² mol ethanol</u>
Liters of solution = 1.2 x 10⁻² moles / 0.200 moles/L = 0.060 L
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Note: Each answer is given with the correct number of significant figures which results from the least number of significant figures in the given used values in each calculation.
