Answer:
(a) C5H8O2
(b) C2H2Cl2
(c) CH2
(d) CH
Explanation:
We need to find the proportion of the atoms in whole numbers. Given the percentages we can calculate the number of moles and find their proportions.
Assume 100 g and given the atomic weights the moles are calculated.
(a) C = 59.9/ 12.01 = 4.98 ≈ 5.00
H = 8.06/1.007 = 8.00
O = 32/15.999 = 2.00
C5H8O2
(b) C= 24.8/12.01 = 2.06≈ 2.00
H = 2.0/1.007 = 1.99 ≈ 2.00
Cl = 73.1/ 35.453 = 2.06 ≈ 2.00
C2H2Cl2
(c) C = 86/12.01 = 7.16
H= 14/1.007 = 13.90
7.16:13.90 ≈ 1:2
CH2
(d) C = 92.30/12.01 = 7.68
H = 7.7 / 1.007 = 7.65
7.68:7.65 ≈ 1:1
CH
amount of CaO that would be produced when 35.5g of CaCO3 decompose on heating (Ca= 40, O = 16, C = 12, H = 1
just put the values to have answer
Answer:
kilograms of sulfur will be emitted from coal plants in two weeks
Explanation:
Power produced by power plants in the United States :P
P=
1 Joule = Watts × Seconds
Watts = Joule/Second
P=
This means that 
Joules of enrgy is produced in one second.
So, energy produced in 2 week:
1 week = 7 days
1 day = 24 hours
1 hour = 3600 seconds
2 week = 2 × 7 × 24 × 3600 s=1,209,600 s
Energy produced in 1,209,600 s: E
Coal has an energy content =
Mass of coal used while producing E amount of energy: m
Percentage of sulfur in coal = 4% by mass
Mass of sulfur produced from 
in 2 weeks:
Dew forms when the air just above the ground is cooled to its dew point. The air above the ground is cooled because the ground radiates heat into space. If there are clouds overhead the clouds reflect the heat back to the ground so it does not cool and o dew forms. If it is windy then the air just above the ground to the dew point and no dew forms. Thus to form dew you need a still clear keeps on getting mixed with the air higher up and the air does not cooled to the dew point and no dew forms.
