2 years ago

What is the energy of a photon with a frequency of 3. 6 × 1015 hz? planck’s constant is 6. 63 × 10–34 j•s.

Physics

1 answer:

GrogVix [38]2 years ago

3 0

Answer:

2.029×10^-18 J

Explanation:

E=hv

E=(3.06×10^15)*(6.63×10^-34)

E=2.029×10^-18 J

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Explanation:

GIVEN DATA:

Radius of ring 73 cm

charge on ring 610 nC

ELECTRIC FIELD p FROM CENTRE IS AT 70 CM

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Electric field due tor ring is guiven as

$E = \frac{KQx}{[x^2+ R^2]^{3/2}}$

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now the eelctric charge at point P is

E = E1 + E2 $2000 = 3714.672 + 1.837\times 10[10} \times q$

solving for q

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