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Nina [5.8K]
2 years ago
10

I require assistance

Physics
2 answers:
gayaneshka [121]2 years ago
5 0

Answer:

1. 10N right

2.41N left

3. 3N left

4. 1N left

5. 31N left

6.0N

Sever21 [200]2 years ago
5 0
Ri
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le
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l
n

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a 1.2 m wire carries a current of 10.0 A in a uniform magnetic field of 0.050T. Find the magnitude of the magnetic force on the
rodikova [14]
To calculate we use the formula for a magnetic force in a current-carrying wire expressed as the product of the current, magnetic field and the length of the wire.
 F = I x L x B

where F is the force on the wire, I is the current flowing on the wire, L is the length of the wire and B is the magnetic field.

F = 10.0 A x 1.2 m x 0.050 T
F = 0.60 N
8 0
3 years ago
A student conducted an experiment to measure the acceleration due to gravity 'g' of a simple pendulum.
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I think i used calulater and it gives me 47.5
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A physical quantity, G, is defined by G = (Original mass x time)/(change in mass), what is the S.I. unit of G ?
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4 0
2 years ago
The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it 0.90 s to reach the floor. Wha
Anna007 [38]

Answer:

The mass of the another block is 60 kg.

Explanation:

Given that,

Mass of block M= 100 kg

Height = 1.0 m

Time = 0.90 s

Let the mass of the other block is m.

We need to calculate the acceleration of each block

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value into the formula

1.0=0+\dfrac{1}{2}\times a\times(0.90)^2

a=\dfrac{2\times1.0}{(0.90)^2}

a=2.46\ m/s^2

We need to calculate the mass of the other block

Using newton's second law

The net force of the block M

Ma=Mg-T

T=Mg-Ma....(I)

The net force of the block m

ma=T-mg

Put the value of T from equation (I)

ma=Mg-Ma-mg

m(a+g)=M(g-a)

m=\dfrac{M(g-a)}{(a+g)}

Put the value into the formula

m=\dfrac{100(9.8-2.46)}{2.46+9.8}

m=59.8\ \approx60\ kg

Hence, The mass of the another block is 60 kg.

8 0
3 years ago
What is the radius of a circle thats the diameter of 480?
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The answer is 12.36. hoped this helped!
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