Answer:
The acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
Explanation:
Let suppose that maximum height of the arc is so small in comparison with the radius of the Earth.
Since the ball is launched upwards, then the ball experiments a free-fall motion, that is, an uniform accelerated motion in which the element is accelerated by gravity. Then, the acceleration experimented by the motion remains constant at every instant and position.
Besides, the gravitational acceleration in the Earth and, in consequence, the acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
Answer:
ΔΦ = -3.39*10^-6
Explanation:
Given:-
- The given magnetic field strength B = 0.50 gauss
- The angle between earth magnetic field and garage floor ∅ = 20 °
- The loop is rotated by 90 degree.
- The radius of the coil r = 19 cm
Find:
calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.
Solution:
- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.
- The strength of magnetic field B and the are of the loop A remains constant. So we have:
Φ = B*A*cos(θ)
ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )
- The initial angle θ_1 between the normal to the coil and B was:
θ_1 = 90° - ∅
θ_1 = 90° - 20° = 70°
The angle θ_2 after rotation between the normal to the coil and B was:
θ_2 = ∅
θ_2 = 20°
- Hence, the change in flux can be calculated:
ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )
ΔΦ = -3.39*10^-6
Answer:
The most common difference between the two is that while conductors allow free flow of electrons from one atom to another, insulators restrict free flow of electrons. Conductors allow electrical energy to pass through them, whereas insulators do not allow electrical energy to pass through them.
Explanation:
Answer:
Height of the racket ball = 0.86 m
Explanation:
Given:
Speed of the tennis ball,
= 31 m/s
Distance covered, 
= 13.3 m
We have to find the height of the racket ball when it left the racket.
Lets say that the time taken by the ball to hit the court be 't' seconds.
⇒ 
⇒ 
⇒ 
⇒ 
seconds
Now we have to find the height lets say that the height is 'h' meter.
⇒ 
...<em>second equation of motion</em>
⇒ 
<em>...initial velocity = 0 and acceleration = gravity </em>
⇒ 
⇒ 
⇒ 
meter.
So the height of the racket ball when it left the racket is of 0.86 m.
