Potassium is a chemical element
Symbol: K
Atomic number: 19
Atomic mass: 39.0983 u ± 0.0001 u
Electron configuration: [Ar] 4s1
Melting point: 146.3°F (63.5°C)
Answer:
17.6510 L
Explanation:
First we should get the number of moles of helium here by Boyle's law
PV=nRT
P=750/760= 0.9868 atm
T=25+273=298 kelvin
R= 0.08206
V= 20L
so
n=PV/RT
n=0.9868×20/0.08206×298
n=0.80707 mol
Then use the same law
V=0.80707×0.08206×263/0.9869=
17.6510L
SO THE VOLUME WILL BE 17.6510 L
Answer:
%KCl = 7.05%
%Water = 92.95%
Explanation:
Step 1: Given data
- Mass of KCl (solute): 36 g
- Mass of water (solvent): 475 g
Step 2: Calculate the mass of the solution
The mass of the solution is equal to the sum of the masses of the solute and the solvent.
m = 36 g + 475 g = 511 g
Step 3: Calculate the mass percentage of the solution
We will use the following expression.
%Component = mComponent/mSolution × 100%
%KCl = 36 g/511 g × 100% = 7.05%
%Water = 475 g/511 g × 100% = 92.95%
Answer:
water moves through diffusion
Answer:
Cl⁻
Explanation:
Definition of atomic radii
The atomic radius is the distance between center of two bonded atoms.
Trend along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase.The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases.
Trend along group:
In group by addition of electron atomic radii increase from top to bottom due to increase in atomic number and addition of extra shell.
In this way Cl⁻ will have the largest atomic radii because one extra electron is added and its atomic number is already greater than fluorine.