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NNADVOKAT [17]
1 year ago
8

A weather forecast for a certain day in an area shows two measurements, 18 degrees Celsius and 25 degrees Celsius. What do these

measurements indicate?
The change in air pressure as you go higher
The change in air temperature as you go higher
The low and high air pressures
The low and high air temperatures
Physics
1 answer:
slamgirl [31]1 year ago
4 0
The low and high air temperatures
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Who is Tim peak where did he come from
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3 years ago
A 1250-kg compact car is moving with velocity v1 =36.2i^+12.7j^m/s. It skids on a frictionless icy patch and collides with a 448
MA_775_DIABLO [31]

Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:

(1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s) = ((1250 + 448) kg) <em>v</em>

where <em>v</em> is the velocity of the system. Solve for <em>v</em> :

<em>v</em> = ((1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s)) / (1698 kg)

<em>v</em> ≈ (30.3 <em>i</em> + 12.0 <em>j</em> ) m/s

7 0
2 years ago
How do we get this equation ??<br><br><br> H=V^2÷R
lesantik [10]

H=\frac{V^2}{R}\times t is the equation that represents the Joule's law of heating.

<h3>Explanation:</h3>

Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to  

1. Square of Current (I²),

2. Resistance of the conductor (R)

3. Time for which current is passed (t)

Hence, Heat generated = H = I^2 Rt .....................(1)

By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).

V\ \alpha\ I\\V=I\times R ...............................................(2)

From (2), Current (I) can be rewritten as

I = \frac{V}{R} ........................................................(3)

Substituting (3) in (1), we get

H = I^2\times R\times t \\=(\frac{V}{R} )^2\times R\times t\\\\=\frac{V^2}{R^2}\times R\times t = \frac{V^2}{R}\times t\\\\ H =\frac{V^2}{R}\times t

3 0
3 years ago
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