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MariettaO [177]
3 years ago
5

Dalton’s theory was identified using light microscope images of atoms. the experimental results of other scientists. water vapor

and air experiments.
Physics
2 answers:
dusya [7]3 years ago
8 0

Water vapor and air experiments

joja [24]3 years ago
6 0

Answer:

C

Explanation:

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HELP ME FAST PLZZ 48 BRAINLY POINTS TO WHO EVER ANSWER!
Elis [28]

Answer:

25

Explanation:

I looked at it and its 25

4 0
3 years ago
Read 2 more answers
what is the specific heat capacity of silver metal if 55.00g of the absored 47.3 calories of heat and temperature rise 15.°c​
igor_vitrenko [27]

Answer:

0.240 J/(g^{\circ}C)

Explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by \Delta T according to the equation

Q=mC_s \Delta T

where

C_s is the specific heat capacity of the substance

In this problem, we have:

m = 55.0 g is the mass of the sample of silver

Q = 47.3 \cdot 4.184 = 197.9 J is the amount of energy supplied to the sample

\Delta T = 15^{\circ}C is the change in temperature of the sample

Solving the equation for C_s, we find the specific heat capacity of silver:

C_s = \frac{Q}{m \Delta T}=\frac{197.9}{(55.0)(15)}=0.240 J/(g^{\circ}C)

3 0
4 years ago
1The density of an of an object with a volume of 60.0 and mass of 400.0g is______
Kobotan [32]
D is the answer
To get the density you divide mass by volume
So the equation is 400/60=d
4 0
3 years ago
The mass of a cm3(cube) stone is 180.
ss7ja [257]

 Density = (mass) / (volume), no matter how large or small the sample is.

We can't calculate the density, because you left out the number for the volume.
Also, you didn't tell us the unit for the mass of 180.

a).  If the mass is 180 grams, then the density is 

                               (180 gm) / (volume) .

b).  No matter how many pieces you crush it into, and
no matter how large or small a piece is, its density is
the same.  (I just wish we knew what the density really is.)

c).  A piece may have 80 grams of mass.  It doesn't "weigh" 80 grams.

Since the density of the whole rock is  (180 gm) / (volume),
the density of any piece of it is  (180 gm) / (volume).

Multiply each side by (volume):   (Density) x (volume) = 180 gm

Divide each side by (density):        Volume = (180 gm) / (density)

We can't calculate the volume of an 80-gm piece, because
we don't know the density.  (That's because you left the volume
out of the question.)

4 0
3 years ago
g If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resi
Anettt [7]
<h2>Question:</h2>

In this circuit the resistance R1 is 3Ω, R2 is 7Ω, and R3 is 7Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be?

Answer:

9.1Ω

Explanation:

The circuit diagram has been attached to this response.

(i) From the diagram, resistors R1 and R2 are connected in parallel to each other. The reciprocal of their equivalent resistance, say Rₓ, is the sum of the reciprocals of the resistances of each of them. i.e

\frac{1}{R_X} = \frac{1}{R_1} + \frac{1}{R_2}

=> R_{X} = \frac{R_1 * R_2}{R_1 + R_2}             ------------(i)

From the question;

R1 = 3Ω,

R2 = 7Ω

Substitute these values into equation (i) as follows;

R_{X} = \frac{3 * 7}{3 + 7}

R_{X} = \frac{21}{10}

R_{X} = 2.1Ω

(ii) Now, since we have found the equivalent resistance (Rₓ) of R1 and R2, this resistance (Rₓ) is in series with the third resistor. i.e Rₓ and R3 are connected in series. This is shown in the second image attached to this response.

Because these resistors are connected in series, they can be replaced by a single resistor with an equivalent resistance R. Where R is the sum of the resistances of the two resistors: Rₓ and R3. i.e

R = Rₓ + R3

Rₓ = 2.1Ω

R3 = 7Ω

=> R = 2.1Ω + 7Ω = 9.1Ω

Therefore, the combination of the resistors R1, R2 and R3 can be replaced with a single resistor with an equivalent resistance of 9.1Ω

4 0
3 years ago
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