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MariettaO [177]

3 years ago

5

Dalton’s theory was identified using light microscope images of atoms. the experimental results of other scientists. water vapor

and air experiments.

2 answers:

dusya [7]3 years ago

8 0

Water vapor and air experiments

joja [24]3 years ago

6 0

Answer:

C

Explanation:

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1. Faça as transformações:

zhannawk [14.2K]

Answer:

$seconds (s) = hours (h) *3,600 ; h = \frac{s}{3,600} \\g = kg * 1,000; kg = \frac{g}{1,000} \\cm = \frac{m}{100};m = cm * 100$

1. a) 0.5 h = 1,800 s

h) 20 cm = 0.2 m

b) 2.0 h = 7,200 s

i) 5.0 kg = 5,000 g

c) 3.5 h = 12,600 s

j) 1.5 kg = 1,500 g

d) 1/4 h = 900 s

k) 450.0 g = 0.45 kg

e) 3.0 m = 300 cm

l) 20.0 g = 0.02 kg

f) 2.5 m = 250 cm

m) 500.0 g = 0.5 kg

g) 0.5 m = 500 mm

n) 1000.0 g = 1 kg

3 0

2 years ago

Which of the following is the best definition of a closed system?

lisov135 [29]

The answer is either

b A system in which Newton's Laws are valid

or

c A system in which there are no external forces.

Explanation:

not a, and not d

There are energy changes in a closed system.

A closed system obeys the conservation laws in its physical description.

4 0

3 years ago

When a magnet is dropped why does it lose its magnetic properties

Veronika [31]

When a magnet is dropped, the domain become unaligned.

3 0

2 years ago

Read 2 more answers

Cellular phones use _____?

dangina [55]

Let's see: frequency of cellular phone waves (GSM phones) is (800-1900 MHz). If we look at the table of the electromagnetic spectrum, we can see that this range is contained within the frequencies of the microwaves, which include waves in the range 300 MHz-300 GHz.

So, summarizing, the correct answer is "microwaves".

3 0

2 years ago

Read 2 more answers

A very long straight wire has charge per unit length 1.44×10-10C/m.

4vir4ik [10]

Answer:

Distance of the point where electric filed is 2.45 N/C is 1.06 m

Explanation:

We have given charge per unit length, that is liner charge density $\lambda =1.44\times 10^{-10}C/m$

Electric field E = 2.45 N/C

We have to find the distance at which electric field is 2.45 N/C

We know that electric field due to linear charge is equal to

$E=\frac{\lambda }{2\pi \epsilon _0r}$ , here $\lambda$ is linear charge density and r is distance of the point where we have to find the electric field

So $2.45=\frac{1.44\times 10^{-10} }{2\times 3.14\times 8.85\times 10^{-12}\times r}$

r = 1.06 m

So distance of the point where electric filed is 2.45 N/C is 1.06 m

3 0

2 years ago