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iren [92.7K]
3 years ago
7

A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac

e of the water. It takes a time of 2.90s for the boat to travel from its highest point to its lowest, a total distance of 0.630m . The fisherman sees that the wave crests are spaced a horizontal distance of 5.60m apart.
1. How much is the wavelength?
express your answers in 3 sig. fig.
2.Find the period of the wave.
3 sig. fig.
3.How fast are the waves traveling?
Express the speed v in meters per second using three significant figures.
4. What is the amplitude A of each wave?
Express your answer in meters using three significant figures.
Physics
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

1.  λ = 5.60 m , 2.  T = 5.80 s  3.  v = 0.966 m/s   4.  A = 0.315 m

Explanation:

1. The definition of wavelength is the distance between two consecutive maximums or minimums, so that the wave is repeated, in this case they give us the distance between two consecutive maximums, therefore

    λ = 5.60 m

2. the period is the time it takes for the wave to start repeating itself, going through the same point. They give time to go from the highest point to the lowest point, which is the time for half a wavelength, so the time for a wavelength is

     T = 2 t

     T = 2 2.90

     T = 5.80 s

3. For all waves the speed is the product of the wavelength by the frequency and the frequency is the inverse of the period

    v = λ f

    f = 1 / T

   v =  λ / T

   v = 5.60 / 5.80

   v = 0.966 m / s

4. The amplitude of the wave is the value of the zero displacement point to the maximum displacement point, give the value between the maximum and minimum displacement

     A = d / 2

     A = 0.63 / 2

     A = 0.315 m

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Calculate the kinetic energy, in joules of a 1160-kg automobile moving at 19.0 m/s.
Rudiy27

Answer:

Explanation:

K.E=1/2 mv²

m=1160 kg

v=19.0 m/s

so k.e=1/2*1160*(19.0)²

K.E=1/2*1160*361

K.E=1/2*418760

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2 years ago
the object on the right gained mass so that it had as much mass as the object on the left, how would the gravitational force bet
kherson [118]

The gravitational force between the objects A. It would increase.

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

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m_1,m_2 are the masses of the two objects

r is the separation between the objects

In this problem, we are told that one of the object (the one on the right) gains mass: this means that, for instance, the value of m_2 increases. We can see from the equation that the gravitational force is directly proportional to the masses: therefore, if one of the masses increases (while the distance between the two objects remains constant), it means that the force also increases.

Therefore, the correct answer is

A. It would increase.

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What is the ratio of the intensities of an earthquake P wave passing through the Earth and detected at two points 14 km and 49 k
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Answer:

\dfrac{I_1}{I_2}=12.25

Explanation:

r_1 = 14 km

r_2 = 49 km

Intensity of a wave is inversely proportional to distance

I\propto \dfrac{1}{r^2}

So,

\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{49^2}{14^2}\\\Rightarrow \dfrac{I_1}{I_2}=12.25

The ratio of the intensities is \dfrac{I_1}{I_2}=12.25

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2 years ago
1. A truck with a mass of 8, 000 kg is traveling at 26.8 m/s when it hits the brakes. A.)What is the momentum of the truck befor
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Answer:

1. A.) The moment of the truck before it hits the brakes is 214,400 kg·m/s

B.) The force it takes to stop the truck is approximately 17,290.4 N

Explanation:

1. A.) The given parameters are;

The mass of the truck, m = 8,000 kg

The velocity of the truck when it hits the brakes, u = 26.8 m/s

Momentum = Mass × Velocity

The moment of the truck = The mass of the truck × The velocity of the truck

Therefore;

The moment of the truck before it hits the brakes = 8,000 kg × 26.8 m/s = 214,400 kg·m/s

B.) The amount of momentum lost when the truck comes to a stop = The initial momentum of the truck

The time it takes the truck to come to a complete stop, t = 12.4 s

The deceleration, "a" of the truck is given by the following kinematic equation of motion

v = u - a·t

Where;

v = The final velocity of the truck = 0 m/s

u = The initial velocity = 26.8 m/s

a = the deceleration of the truck

t = The time of deceleration of the truck = 12.4 s

Substituting the known values gives;

0 = 26.8 - a × 12.4

Therefore;

26.8 = a × 12.4

a = 26.8/12.4 ≈ 2.1613

The deceleration (negative acceleration) of the truck, a ≈ 2.1613 m/s²

Force = Mass × Acceleration

The force required to stop the truck = The mass pf the truck × The deceleration (negative acceleration) given to the truck

∴ The force it takes to stop the truck = 8,000 kg × 2.1613 m/s² ≈ 17,290.4 N.

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