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IRISSAK [1]
3 years ago
8

An object with a initial velocity of 0m/s accelerates at a rate of 4m/s how much time did it take to go 88m?

Physics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

6.633s

Explanation:

For this equation we use the following kinematic equation:

^D = Vi(t)+(1/2)(a)(t)^2

88m-0m = 0m/s(t)+(0.5)(4m/s^2)(t)^2

88m = 2m/s^2(t^2)

t^2 = 44s

t = sqrt(44)

t = 6.633s

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A 25N force is acting on a body moving on a straight line with Initial momentum 20 kam's. Find the final momentum after 4 second
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<h3>What is momentum?</h3>

Momentum can be described as the multiplication of the mass and velocity of an object. Momentum is a vector quantity as it carries magnitude and direction.

If m is an object's mass and v is its velocity then the object's momentum p is: {\displaystyle \mathbf {p} =m\mathbf {v} . The S.I. unit of measurement of momentum is kg⋅m/s, which is equivalent to the N.s.

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