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3 years ago

An object with a initial velocity of 0m/s accelerates at a rate of 4m/s how much time did it take to go 88m?

Physics

1 answer:

Citrus2011 [14]3 years ago

3 0

Answer:

6.633s

Explanation:

For this equation we use the following kinematic equation:

^D = Vi(t)+(1/2)(a)(t)^2

88m-0m = 0m/s(t)+(0.5)(4m/s^2)(t)^2

88m = 2m/s^2(t^2)

t^2 = 44s

t = sqrt(44)

t = 6.633s

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Yes, It has a stored energy in that stone.

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3 years ago

If i apply 280 n of force to a 40kg object, what will it's acceleration be?

nika2105 [10]

Answer:

f=ma

f=280N

m=40kg

a=?

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a=70N/kg

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3 years ago

_________ is a layer of the earth that is classified not by composition

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Answer:

Asthenosphere

Explanation:

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3 years ago

Monochromatic light is incident on (and perpendicular to) two slits separated by 0.200 mm, which causes an interference pattern

marusya05 [52]

Answer:

I = 0.636*Imax

Explanation:

(a) To find the fraction of the maximum intensity at a distance y from the central maximum you use the following formula:

$I=I_{max}cos^2(\frac{\pi d}{\lambda L}y)$ (1)

I: intensity of light

Imax: maximum intensity of light

d: separation between slits = 0.200mm = 0.200 *10^-3 m

L: distance from the screen = 613cm = 0.613 m

y: distance to the central peak of the interference pattern

λ: wavelength of light = 656.3 nm = 656.3 *10^-9 m

You replace the values of all variables in the equation (1):

$I=I_{max}cos^2(\frac{\pi (0.200*10^{-3}m)}{(656.3*10^{-9}m)(0.613m)}0.600m)\\\\I=I_{max}cos^2(937.06)=0.636I_{max}$

Hence, the fraction of the maximum intensity is I = 0.636*Imax

6 0

3 years ago

3.50 µf capacitor has a charge with a magnitude of 4.50 µC on each parallel plate. Find the potential difference between the pla

n200080 [17]

Answer:

b) 1.29 V

Explanation:

Potential Difference: This is the work done when one coulomb of charge moves from one point to another in an electric field

The expression for the potential difference is

Q = CV .................... Equation 1

Where Q = amount of charge, C = Capacitance of the capacitor, V = potential difference.

Making V the subject of the equation,

V = Q/C................. Equation 2

Given: Q = 4.5 µC = 4.5×10⁻⁶ C, C = 3.5 µF = 3.5×10⁻⁶ F

Substituting into equation 2

V = 4.5×10⁻⁶ /3.5×10⁻⁶

V = 1.2857 V

V ≈ 1.29 V.

Hence the right option is b) 1.29 V

8 0

3 years ago