1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IRISSAK [1]
3 years ago
8

An object with a initial velocity of 0m/s accelerates at a rate of 4m/s how much time did it take to go 88m?

Physics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

6.633s

Explanation:

For this equation we use the following kinematic equation:

^D = Vi(t)+(1/2)(a)(t)^2

88m-0m = 0m/s(t)+(0.5)(4m/s^2)(t)^2

88m = 2m/s^2(t^2)

t^2 = 44s

t = sqrt(44)

t = 6.633s

You might be interested in
What is the net force on a bathroom scale when a 150-pound person stands on it
andreev551 [17]

Answer:

Zero, the support force and gravitational force together equal a zero net force

Explanation:

7 0
3 years ago
Work and power!
Tema [17]

Answer:

The work done in a unit of time is C. Power.

Explanation:

Hope this helps

5 0
3 years ago
How far from the surface of Earth is the magnitude of Earth's gravitational field equal to 7.86 N/kg?
AfilCa [17]

Answer:

7.48 x 10⁵ m

Explanation:

g = 7.86 N/kg

M = 5.97 x 10²⁴ kg, R = 6.37 x 10⁶ m.

Find height h

g = GM/(R + h)²

(R + h)² = GM/g = 6.67 x 10⁺¹¹ x 5.97 x 10²⁴ /7.86 = 5.066 x 10¹³

R + h = 7.12 x 10⁶ m

so

h =  7.12 x 10⁶ - 6.37 x 10⁶ = 7.48 x 10⁵ m

4 0
2 years ago
A length change 0.08 m will occur for an object that is L= 56 m long. If the coefficient of thermal expansion is5.3 x 10 /C and
ArbitrLikvidat [17]

Answer:

Increase in temperature =  269.54 °C

Explanation:

We have equation for thermal expansion

          ΔL = LαΔT

Change in length, ΔL = 0.08 m

Length, L = 56 m

Coefficient of thermal expansion, α = 5.3 x 10⁻⁶ °C⁻1

Change in temperature, ΔT = T - 253

Substituting

          0.08 = 56 x 5.3 x 10⁻⁶ x (T - 253)

         (T - 253) = 269.54

           T = 522.54 °C

Increase in temperature =  269.54 °C      

4 0
3 years ago
A 4.80 Kg watermelon is dropped from rest from the roof of an 18.0 m building. Calculate the work done by gravity on the waterme
Nonamiya [84]

Answer:

Work, W = 846.72 Joules

Explanation:

Given that,

Mass of the watermelon, m = 4.8 kg

It is dropped from rest from the roof of 18 m building. We need to find the work done by the gravity on the watermelon from the roof to the ground. It is same as gravitational potential energy i.e.

W = mgh

W=4.8\ kg\times 9.8\ m/s^2\times 18\ m

W = 846.72 Joules

So, the work done by the gravity on the watermelon is 846.72 Joules. Hence, this is the required solution.

7 0
3 years ago
Other questions:
  • A 10N force pulls to the right and friction opposes 2N. If the object is 20kg,find the acceleraton.
    9·2 answers
  • Who was the first russian to orbit the earth
    13·2 answers
  • A bicyclist travels 60.0 kilometers in 3.5 hours. What is the cyclist's average speed? Note: Average speed is the total distance
    10·1 answer
  • What is a star called that dies peacefully​
    11·2 answers
  • Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 25.0 m above water wit
    8·1 answer
  • 1. How would the motion of a pendulum change at high altitude like a high mountain top? How would the motion change under weight
    7·1 answer
  • Which of the following scenerios fits all of the criteria for the two-source interference equations to be valid?
    5·1 answer
  • Which measurement is used to determine if an object has balanced forces
    13·1 answer
  • Science
    5·1 answer
  • PLEASE HELP ME WITH THIS ONE QUESTION
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!