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3 years ago

An object with a initial velocity of 0m/s accelerates at a rate of 4m/s how much time did it take to go 88m?

Physics

1 answer:

Citrus2011 [14]3 years ago

3 0

Answer:

6.633s

Explanation:

For this equation we use the following kinematic equation:

^D = Vi(t)+(1/2)(a)(t)^2

88m-0m = 0m/s(t)+(0.5)(4m/s^2)(t)^2

88m = 2m/s^2(t^2)

t^2 = 44s

t = sqrt(44)

t = 6.633s

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Answer:

Moro reflex

Explanation:

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3 years ago

A pipe is horizontal and carries oil that has a viscosity of 0.14 Pa s. The volume flow rate of the oil is 5.3 × 10-5 m3/s. The

Liula [17]

Answer:

Explanation:

Given

$\mu =0.14 Pa.s$

Volume Flow rate $Q=5.3\times 10^{-5} m^3/s$

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According to Hagen-Poiseuille Equation

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$P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}$

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3 years ago

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Answer:

$q=1\times10^{-8}C$

Explanation:

Let the charge on the ball bearing is q.

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By use of Coulomb's law in electrostatics

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By substituting the values

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3 years ago

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anygoal [31]

Answer:

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