The correct answer is B, widespread pollution. If you look closely, you can see that the other answers are not problems at all, but benefits! :)
Answer:
t = 120.5 nm
Explanation:
given,
refractive index of the oil = 1.4
wavelength of the red light = 675 nm
minimum thickness of film = ?
formula used for the constructive interference

where n is the refractive index of oil
t is thickness of film
for minimum thickness
m = 0


t = 120.5 nm
hence, the thickness of the oil is t = 120.5 nm
Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:

The minimun wall thickness:
