Answer:
minimum number of photon is 4.05 × 
Explanation:
given data
energy = 50 keV = 50 × 
eV = 50 × × 1.602× 
J
thickness = 10^-3
contrast = 1%
to find out
number of incident photons
solution
we know here equation that is
E = n × h × ν .......................1
put here all these value
50 × = n × 6.6× 
× c/ 1× 
50 × × 1.602× = n × 6.6× ×( 3 × 
/ 1× )
solve it and find n
n = 4.05 ×
so here minimum number of photon is 4.05 ×
Yes sirrr but at least you know now
The correct answer to the question is : A) The velocity of the cart after it hits the wall.
EXPLANATION:
Before answering this question, first we have to understand impulse.
Impulse of a body is defined as the change in momentum or the product of force with time.
Mathematically impulse = m ( v- u ).
Here, v is the final momentum and u is the initial momentum.
Hence, we need the velocity of the cart after it hits the wall in order to calculate the impulse of the lab cart.
Answer:
Eletromagnetic radiation which is also known as visible light.
Explanation:
