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Delicious77 [7]
3 years ago
13

Which of the following everyday phenomenon are based on the Faraday's effect? a. using your TV remote to turn it on and off b. r

eading data from your computer's hard drive c. playing a CD/DVD swiping your credit/debit card at the market d. playing one of your parent's ancient VHS tap.
Physics
1 answer:
Tcecarenko [31]3 years ago
3 0

Answer:

b. reading data from your computer's hard drive

Explanation:

Reading data from compact hard disc is an operation which is based ob kerr effect or Faraday effect . This effect involves rotation of plane of polarization of light when light passes through  a magnetic field. In order to read data from disc , a low intensity laser light is made to fall upon the disc . On reflection,

the plane of polarization of laser light  is rotated . The extent of rotation depends the extent of magnetization of magnetic disc. In this way information stored in the form of magnetic field is converted into information in the form of light .

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If you designed a rollercoaster, how might you design it? Would you have friction?
kvasek [131]
Yes, because you would need friction to slow down the rollercoaster to a stop. 
4 0
4 years ago
A mass is attached to a spring with an unknown spring constant. The spring gains 10 J of elastic potential energy if stretched b
Firlakuza [10]

From the given information in the question, the correct option is Option 1: 14 cm.

A non-stretched elastic spring has a conserved potential energy which gives it the ability to perform work. The elastic potential energy can be expressed as:

PE = \frac{1}{2} k x^{2}

Where PE is the energy, k is the spring constant and x is extension.

i. Given that: PE = 10 J and x = 10 cm, then;

PE = \frac{1}{2} k x^{2}

10 = \frac{1}{2} k 10^{2}

20 = 100k

k = 0.2 J/cm

ii. To determine how far the spring is needed to be stretched, given that PE = 20 J.

PE = \frac{1}{2} k x^{2}

20 = \frac{1}{2} (0.2) x^{2}

40 = 0.2 x^{2}

x^{2} = 200

x = \sqrt{200}

  = 14.1421

x = 14.14 cm

So that;

x is approximately 14.00 cm.

Thus, the spring need to be stretched to 14.00 cm to give the spring 20 J of elastic potential energy.

For more information, check at: brainly.com/question/1352053.

8 0
3 years ago
1. A soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of
lana66690 [7]

Answer:

Height of cliff = S = 20 m (Approx)

Explanation:

Given:

Initial velocity = 8 m/s

Distance s = 16 m

Starting acceleration (a) = 0

Computation:

s = ut + 1/2a(t)²

16 = 8t

t = 2 sec

Height of cliff = S

Gravitational acceleration = 10 m/s

S = 1/2a(t)²

S = 1/2(10)(2)²

Height of cliff = S = 20 m (Approx)

3 0
3 years ago
Consult Interactive Solution 10.37 to explore a model for solving this problem. A spring is compressed by 0.0647 m and is used t
padilas [110]

Answer:

\omega=32.14\ rad/s

Explanation:

Given that,

The compression in the spring, x = 0.0647 m

Speed of the object, v = 2.08 m/s

To find,

Angular frequency of the object.

Solution,

We know that the elation between the amplitude and the angular frequency in SHM is given by :

v=\omega\times A

A is the amplitude

In case of spring the compression in the spring is equal to its amplitude

\omega=\dfrac{v}{A}

\omega=\dfrac{2.08\ m/s}{0.0647\ m}

\omega=32.14\ rad/s

So, the angular frequency of the spring is 32.14 rad/s.

4 0
3 years ago
You climb to the top of a ladder. You drop a a ball from height H, it reaches the ground with speed V if there is no air resista
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Answer:

heymelissa its amanda i hate ms spearman

Explanation:

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6 0
3 years ago
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