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alex41 [277]
3 years ago
6

A compressed spring has elastic potential energy. Please select the best answer from the choices provided T F

Physics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Answer: True

Explanation:

As the spring is compressed, it acumulates energy, and the spring "wants to release that energy". This acumulated energy, (potential energy) is called "elastic potential energy" because of the elastical nature of the spring, that when compressed it wants to return to the original shape. So the sentence is true

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Answer:

B is the best answer for the question

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How does earths magnetic field protect us from solar flares
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Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation.

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Help it’s actually physical science but plz help
Butoxors [25]
The correct answer is B
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3 years ago
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.10 104 rad/s to an angular speed of 3.14
Anestetic [448]

Answer:

3.63 s

Explanation:

We can solve the problem by using the equivalent SUVAT equations for the angular motion.

To find the angular acceleration, we can use the following equation:

\omega_f^2 - \omega_i ^2 =2 \alpha \theta

where

\omega_f = 3.14\cdot 10^4 rad/s is the final angular speed

\omega_i = 1.10 \cdot 10^4 rad/s is the initial angular speed

\theta= 2.00 \cdot 10^4 rad is the angular distance covered

\alpha is the angular acceleration

Re-arranging the formula, we can find \alpha:

\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}=\frac{(3.14\cdot 10^4 rad/s)^2-(1.10\cdot 10^4 rad/s)^2}{2(2.00\cdot 10^4 rad)}=2.16\cdot 10^4 rad/s^2

Now we want to know the time the bit takes starting from rest to reach a speed of \omega_f=7.85\cdot 10^4 rad/s. So, we can use the following equation:

\alpha = \frac{\omega_f-\omega_i}{t}

where:

\alpha=2.16\cdot 10^4 rad/s^2 is the angular acceleration

\omega_f = 7.85\cdot 10^4 rad/s is the final speed

\omega_i = 0 is the initial speed

t is the time

Re-arranging the equation, we can find the time:

t=\frac{\omega_f-\omega_i}{\alpha}=\frac{7.85\cdot 10^4 rad/s-0}{2.16\cdot 10^4 rad/s^2}=3.63 s

4 0
3 years ago
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What is the mass of a person running at 2.5 m/s with momentum of<br> 200 kg m/S
kondor19780726 [428]

Answer:

m = 80 kg

Explanation:

p = m × v

200 = m × 2.5

2.5m = 200

m = 200/2.5

m = 80 kg

5 0
3 years ago
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