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Blizzard [7]
3 years ago
8

Convert a mass defect of 0.115 g to (a) Joules and (b) MeV

Chemistry
1 answer:
timofeeve [1]3 years ago
7 0

Calculate the mass defect and nuclear binding energy of an atom ... To convert to joules per nucleon, simply divide by the number of nucleons.

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What planet is characterized by rings of ice particles?
iris [78.8K]

Saturn has the most extensive ring system in our solar system & most of the particles floating around in the ring are ice...


Answer=Saturn

5 0
3 years ago
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Minerals form from bodies of water by the process of _____. precipitation melting cooling condensation
Zielflug [23.3K]
<span>Precipitation is the answer. i Hope i helped :3</span>
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3 years ago
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Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n
natta225 [31]

Answer: Mass Of CFC that needs to evaporate for the freezing of water = 328.24 g

Explanation: Heat gained by the CFC = Heat lost by water

Heat lost by water = Heat required to take water's temperature to 0°c + Heat required to freeze water at 0°c

Heat required to take water's temperature from 33°c to 0°c = mCΔT

m = 201g, C = 4.18 J/(gK), ΔT = 33

mCΔT = 201 × 4.18 × 33 = 27725.94 J

Heat required to freeze water at 0°c = mL

m = 201g, L = 334 J/g

mL = 201 × 334 = 67134 J

Heat gained by CFC to vaporize = mH = 27725.94 + 67134 = 94859.94 J

H = 289 J/g, m = ?

m × 289 = 94859.9

m = 328.24 g

QED!!

7 0
3 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
4 years ago
Blank + BaCl2 = BaSO4 + 2NaCl
crimeas [40]

The blank is filled by Na₂SO₄, and the complete equation for the double displacement reaction is:

Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl

<h3>What is a double displacement reaction?</h3>

It is a reaction in which both reactants exchange anions and cations.

Let's consider the following incomplete double displacement reaction.

_____ + BaCl₂ = BaSO₄ + 2 NaCl

If we compare the left and right sides, we can see that the missing ions in the left side are Na⁺ and SO₄²⁻. Thus, the missing compound is Na₂SO₄. The complete equation is:

Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl

Learn more about double displacement here: brainly.com/question/23918356

#SPJ1

5 0
2 years ago
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