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Blizzard [7]
3 years ago
8

Convert a mass defect of 0.115 g to (a) Joules and (b) MeV

Chemistry
1 answer:
timofeeve [1]3 years ago
7 0

Calculate the mass defect and nuclear binding energy of an atom ... To convert to joules per nucleon, simply divide by the number of nucleons.

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What is an energy conserved system ?
grin007 [14]

Answer: In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.

Explanation:

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6 0
3 years ago
A student was titrating the calcium and water solution and notice the formation of bubbles in the flask. which description would
labwork [276]
Hi!

When titrating Calcium and Water solution, if there is some CaCO3 in the solution, the following reactions may occur in acid solution:

CaCO₃ + H⁺ → Ca⁺² + HCO₃⁻

HCO₃⁻ + H⁺ ↔ H₂CO₃ → CO₂ (g) + H₂O

The bubbles are from CO₂ that is being developed from an acidic solution of CaCO₃

4 0
3 years ago
Select the most acidic solution from these options. select the most basic (alkaline) solution from these options. select the lea
Gala2k [10]
Most acidic: solution B, pH = 1
Most Basic: solution C, pH = 13
Least acidic: solution A, pOH = 1
8 0
3 years ago
Read 2 more answers
The following reaction: HF(aq) <--> H+(aq) + F-(aq) has an equilbirum constant (K) value of 7.2 x 10-4. This means that th
andriy [413]

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

<h3>What is the equilibrium constant?</h3>

In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.

On the other hand, when we have a case that the equilibrium constant is small and is not so large, then the reaction does not proceed essentially to completion.

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

Learn more about equilibrium constant:brainly.com/question/10038290

#SPJ1

6 0
1 year ago
How many grams of octane (C8H18) must be burned to produce 300.0g of CO2?
nika2105 [10]

Answer:

m_{C_8H_{18}}=85.67gC_8H_{18}

Explanation:

Hello there!

In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

m_{C_8H_{18}}=300.0gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molC_8H_{18}}{25molO_2}*\frac{114.22gC_8H_{18}}{1molC_8H_{18}}   \\\\m_{C_8H_{18}}=85.67gC_8H_{18}

Regards!

6 0
3 years ago
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