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ruslelena [56]
1 year ago
10

Using the equation 40kJ+2SO3(g)-->2SO2(g) + O2(g), if pressure is added what way

Chemistry
1 answer:
Ad libitum [116K]1 year ago
6 0

In an equation, 40kJ + 2SO₃ (g) -->2SO₂(g) + O₂(g), if pressure added, the equilibrium shifts to the left side of the reaction because it has fewer moles of gas.

<h3>What is Le Ch atelier's principle?</h3>

Le Ch atelier's principle states that if the pressure is added in a nay reaction, then the equilibrium will be shifted toward the side where there are fewer atoms.

In this case, there are fewer moles on the left side.

Thus, when pressure is added, the equilibrium shift to the left side due to Le Ch atelier's principle.

Learn more about Le Ch atelier's principle

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An acid increases the hydroxide ion concentration of water.<br>True<br>or<br>False
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You find a compound composed only of element "X" and hydrogen, and know that it is 91.26% element X by mass. Each molecule has 2
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X3H8<span>so the ratio of 1:2.67 is still maintained. The mass percent tells you that out of every 100g of compound, 91.26g is element X, so the other 8.74g must be H. Dividing each mass by the number of moles in the formula gets us the molar mass of each element (approximately). DIviding 8.74g by 8 gets 1.09, roughly the molar mass of hydrogen. Dividing 91.26g by 3 gets us 30.4, roughly the molar mass of phosphorus. Element X is most likely phosphorus</span>
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Predict the missing product of this equation<br><br><br>1 MgF2 + 1 Li2CO3 -&gt; 1 ______ +2LiF
ch4aika [34]

Answer:

MgCO₃

Explanation:

From the question given above, we obtained:

MgF₂ + Li₂CO₃ —> __ + 2LiF

The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:

MgF₂ (aq) —> Mg²⁺ + 2F¯

Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯

MgF₂ + Li₂CO₃ —>

Mg²⁺ + 2F¯ + 2Li⁺ + CO₃²¯ —> Mg²⁺CO₃²¯ + 2Li⁺F¯

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:

MgF₂ + Li₂CO₃ —> __ + 2LiF

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Therefore, the missing part of the equation is MgCO₃

8 0
2 years ago
A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?
neonofarm [45]

Answer:

\boxed {\boxed {\sf 40.4299 \ Joules}}

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

PE= m \times g \times h

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

  • m= 1.85 kg
  • g= 9.8 m/s²
  • h= 2.23 m

Substitute the values into the formula.

PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m

Multiply the first 2 numbers together.

PE=18.13 \ kg*m/s^2 *2.23 \ m

Multiply again.

PE= 40.4299 \ kg*m^2/s^2

  • 1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
  • Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

PE= 40.4299 \ J

The textbook has <u>40.4299 Joules of potential energy.</u>

7 0
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