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valentina_108 [34]
3 years ago
10

Whats 4×5÷6×9÷5×3÷9​

Mathematics
2 answers:
yarga [219]3 years ago
5 0

Answer:

Step-by-step explanation:

your answer is 2

sp2606 [1]3 years ago
3 0
The answer is 2 hoped this helped
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3/4x+7/8=4 1/4 please help me
Orlov [11]

Answer:

4 1/2

Step-by-step explanation:

4 0
1 year ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
Fine the two consecutive whole numbers the square root is between: √(26) & √(60)
blondinia [14]
The consecutive number = 1,2 or 7,8 not 5,8 etc

whole number = 1,6,100 

square root of 60 = 7.746

so, if you want to know two consecutive whole numbers b/w swrt of 60
that would be

7 less than 7.6 less than 8

 
3 0
3 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
A High School soccer team is going to Columbus, Ohio to see a professional soccer game. A coordinate grid is superimposed on the
finlep [7]

Answer: The coordinate are

( 5 , 2.5 )

Distance = 5

Step-by-step explanation:

The coordinates of the rest stop will be the mid point between the high school is at point (3, 4) and the stadium in Columbus at point (7, 1).

Mid point = (X1 +X2)/2 , (Y1+Y2)/2

(3+7)/2 , (4+1)/2 = ( 5 , 2.5 )

The approximate distance between the high school and the stadium will be

D^2 = (7-3)^2 +( 4-1)^2

Where D = distance

D^2 = 4^2 + 3^2

D = 5

4 0
3 years ago
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