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hram777 [196]
2 years ago
15

Helpp

Chemistry
2 answers:
galben [10]2 years ago
8 0
The answer is C) Temperature
Colt1911 [192]2 years ago
7 0
I’m pretty sure it’s current , D
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A 30.7 g sample of Strontium nitrate, Sr(NO3)2•nH2O, is heated to a constant mass of 22.9 g. Calculate the hydration number.
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  • Number of moles of Sr (NO₃)₂ = 22.9 g / 211.63 g/mol =  0.108 mol

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  • 0.439 mol H₂O / 0.108 mol Sr(NO₃)₂ ≈  4 mol H₂O : 1 mol Sr (NO₃)₂

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