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NeX [460]
3 years ago
8

Balance the equation

Chemistry
1 answer:
lukranit [14]3 years ago
4 0
If a link says to click on it please don’t it’s a scam
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Select The on that most applys<br><br><br> Will mark brainliest
sdas [7]

Answer:

A and C

Explanation:

7 0
3 years ago
When the reaction h3po4(aq) ca(oh)2(aq)→ occurs what is the formula for the salt formed?
Georgia [21]
2H3PO4 + 3Ca(OH)2 ➡ Ca3(PO4)2 + 6H2O.

Hence salt formed is Ca3(PO4)2.
Hope this helps, have a nice day!
7 0
3 years ago
Read 2 more answers
. KMnO4 oxidizes ethyl benzene to benzoic acid. If this reaction generally results in a 40 % experimental yield, how many grams
lyudmila [28]

Answer:

530.835 g

Explanation:

First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:

  • 244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid

Theoretically,<em> one mol of ethyl benzene would produce one mol of benzoic acid</em>. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.

With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:

  • 2.00 moles benzoic acid * \frac{1molEthylBenzene}{0.4molBenzoicAcid} = 5.00 moles ethyl benzene

Finally we <u>convert moles of ethyl benzene </u>(C₈H₁₀)<u> into grams</u>, using its <em>molar mass</em>:

  • 5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene
7 0
3 years ago
If 0.25 mol of br2 and 0.55 mol of cl2 are introduced into a 3.0-l container at 400 k, what will be the equilibrium concentratio
Vladimir79 [104]
Answer is: <span> the equilibrium concentration of Br</span>₂ is 0,02 mol/L.<span>
</span>Chemical reaction: Br₂ + Cl₂ → 2BrCl.
Kc = 7,0.
c₀(Br₂) = 0,25 mol ÷ 3 L.
c₀(Br₂) = 0,083 mol/L.
c₀(Cl₂) = 0,55 mol ÷ 3 L.
c₀(Cl₂) = 0,183 mol/L.
Kc = c(BrCl)² ÷ c(Br₂) · c(Cl₂).
7 = (2x)² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
7 = 4x² ÷ (0,083 mol/L - x) · (0,183 mol/L - x).
Solve q<span>uadratic equation: x = 0,063 mol/L.
</span>c(Br₂) = 0,083 mol/L - 0,063 mol/L = 0,02 mol/L.


6 0
3 years ago
Read 2 more answers
A solution is made by mixing 31 g of heptane C7H16 and 42 g of chloroform CHCl3.
levacccp [35]

Answer:

The mol fraction of heptane in this solution is 0.47

Explanation:

Step 1: Data given

Mass of heptane = 31.00 grams

Molar mass of heptane = 100.21 g/mol

Mass of chloroform = 42.00 grams

Molar mass of chloroform = 119.38 g/mol

Step 2: Calculate moles heptane

moles heptane = 31.00 grams / 100.21 g/mol

moles heptane = 0.309 moles

Step 3: Calculate moles chloroform

moles chloroform = 42.00 grams / 119.38 g/mol

moles chloroform = 0.352 moles

Step 4: Calculate total moles

Total moles = moles heptane + moles chloroform

Total moles = 0.309 moles + 0.352 moles = 0,661 moles

Step 5: Calculate mol fraction of heptane

Mol fraction heptane = moles heptane / total moles

Mol fraction heptane = 0.309 moles / 0.661 moles

Mol fraction heptane = 0.47

The mol fraction of heptane in this solution is 0.47

8 0
4 years ago
Read 2 more answers
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