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nexus9112 [7]
2 years ago
10

Pls help the question is here (12points) DUE TO DAY

Mathematics
1 answer:
scZoUnD [109]2 years ago
5 0

Answer:

\bf Area= 90\;in

Step-by-step explanation:

<u>Area of ABCD = L * W</u>

\bf 6\times 12

\bf 72 \;in^2

<u>Area of EFGC:- L * W</u>

\bf 6 \times 3

\bf 18\; in^2

<u>Now, the area of the combind rectangles:-</u>

ABCD + EFGC

\bf 72+18

\boxed{\bf 90\; in}

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Convert the following percent to a fraction, then reduce to lowest terms: <br> 66.67%
34kurt

Answer: It is 2/3

Step-by-step explanation:

6 0
3 years ago
Lim x-&gt;pi/3 ((2cosx-1)/(tan^2x-3))
beks73 [17]

You can check that the limit comes in an undefined form:

\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\dfrac{0}{0}

In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)

and

\dfrac{\text{d}}{\text{d}x}\tan^2(x)-3 = 2\dfrac{\tan(x)}{\cos^2(x)}=\dfrac{2\sin(x)}{\cos^3(x)}

So, we have

\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)

6 0
3 years ago
I really need help, can someone please help me on both questions​
cupoosta [38]

Answer:

See attached

Step-by-step explanation:

In the questions, find the equation of the dash line then apply the appropriate inequality sign.

In the first one, take points (-3,2) and (0,1) find the gradient and slope of the line.

slope of line, m=Δy/Δx

Δy=1-2=-1

Δx= 0--3=3

m= -1/3

Finding the equation of the line;

y-1/x-0 = -1/3

3y-3 =-x

3y=-x+3

y=-1/3 x+1

The inequality can be ;

y> -1/3 x +1 or y<-1/3 x +1  depending on the shaded region as attached

In 2.

You have two graphs that provide the solution of the inequality.

In the graph represented by line 1, where you have points (-3,-4) and (-5,-5)

The slope will be,

m=-5--4/-5--3

m=-5+4/-5+3

m=-1/-2 = 1/2

The equation will be;

y--4/x--3= 1/2

y+4/x+3= 1/2

2y+8=x+3

2y=x+3-8

2y=x-5

y=1/2x -2.5

In the line with points (-3,-4) and (1,-6)

m=-6--4/1--3

m=-6+4/1+3

m=-2/4 = -1/2

Finding the equation of the line

y--4/x--3 = -1/2

2(y+4) = -1 (x+3)

2y+8 =-x-3

2y=-x-3-8

2y=-x-11

y= -1/2x-5.5

The inequality can be ;

y>1/2x + 2.5

y> -1/2x -5.5

or

y< 1/2 x +2.5

y< -1/2x-5.5

Depending on the area shaded as show in the attached graphs

Learn more

  • Solve inequality using graphs https://brainly.in/question/5768234
  • Solution of inequality using graphs brainly.com/question/11234618

Keywords : Inequalities, graph solutions

#LearnwithBrainly

3 0
3 years ago
I need help... how do you solve this? I'm so sorry i just dont understand it
Novosadov [1.4K]
I need a question or a problem to solve??
6 0
3 years ago
Tape diagram make an equation 6t 9
natta225 [31]

Answer:

The answer would be 0.6666666666666666666666666666666666666666667

Step-by-step explanation:

6/9 equals 0.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666667

6 0
3 years ago
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