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2 years ago

The ____ of emitted light depends directly on the energy between the two orbits and this determines the color of the light

1 answer:

7 0

The frequency of emitted light is directly proportional to the energy between the two orbits and this determines the color of the light.

<h3>What is light?</h3>

Light can be defined as a form of electromagnetic waves that does not require any medium for its propagation. This ultimately implies that, light is a form of wave that is generally referred to as a visual signal because it can be seen with the eyes.

According to the model of light wave, the frequency of emitted light is directly proportional to the energy between the two orbits and this determines the color of the light.

In conlcusion, the frequency of emitted light is highly dependent on the energy between the two (2) orbits.

Read more on energy here: brainly.com/question/1242059

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Complete the following table with the appropriate units of measurement. Word bank: gram, meter, kelvin, liter, second, grams/cm3

lara31 [8.8K]

mass gram, time sec, temp kelvin, vol liter, dens grams/cm3

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3 years ago

Read 2 more answers

A single-turn circular loop of radius 6 cm is to produce a field at its center that will just cancel the earth's field of magnit

djverab [1.8K]

Answer:

The current is $I = 6.68 \ A$

Explanation:

From the question we are told that

The radius of the loop is $r = 6 \ cm = 0.06 \ m$

The earth's magnetic field is $B_e = 0.7G= 0.7 G * \frac{1*10^{-4} T}{1 G} = 0.7 *10^{-4} T$

The number of turns is $N =1$

Generally the magnetic field generated by the current in the loop is mathematically represented as

$B = \frac{\mu_o * N * I}{2 r }$

Now for the earth's magnetic field to be canceled out the magnetic field generated by the loop must be equal to the magnetic field out the earth

$B = B_e$

=> $B_e = \frac{\mu_o * N * I }{ 2 * r}$

Where $\mu$ is the permeability of free space with value $\mu _o = 4\pi * 10^{-7} N/A^2$

$0.7 *10^{-4}= \frac{ 4\pi * 10^{-7} * 1 * I}{2 * 0.06}$

=> $I = \frac{2 * 0.06 * 0.7 *10^{-4}}{ 4\pi * 10^{-7} * 1}$

$I = 6.68 \ A$

3 0

3 years ago

Which device is using a motor? A. A water heater creates heat energy from electric energy. B. A waterfall rotates a waterwheel t

Mumz [18]

Answer:

C is the right answer.

Body massager uses electrical energy to move back and forth. In this sense, a motor is being used for the operation

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3 years ago

A uniform linear charge of 2.0 nC/m is distributed along the x axis from x = 0 to x = 3 m. What is the x component of the electr

balu736 [363]

Answer:

The x component of the electric field at y=2m is $E_{x}=17.97\frac{N}{C}$

Explanation:

For a linear charge, using Gauss Law, we get that the Electric field (radial) has the following form

$E=\frac{\lambda}{2\pi\epsilon_{0}r}$

where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data. So

$E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}$

is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.

4 0

3 years ago

The total charge that an automobile battery can supply without being recharged is given in terms of Ampere-hours. A typical 12-V

anyanavicka [17]

Answer:

7 hours

Explanation:

The total charge contained in the battery is

$Q = 49 A \cdot h$

And this is a charge, since it is a current multiplied by a time:

$Q=It$

The current drawn by each headlight (which is the charge consumed per second) is

$I=3.5 A$

Since we have two headlight, the total current drawn is

$I=3.5 \cdot 2 = 7 A$

Therefore, the total charge consumed by the two headlights each hour is

$q = I \cdot h = 7 A \cdot h$

So, the time before the battery is dead is

$t=\frac{Q}{q}=\frac{49 Ah}{7Ah}=7 h$

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3 years ago