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2 years ago

Im literally gonna cry . what is this

Chemistry

2 answers:

Vlad1618 [11]2 years ago

6 0

Ok I will!!!!!!!!!!!

Dvinal [7]2 years ago

5 0

What is the picture lol , it looks like it was took on a calculator....

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How many joules of energy is required to bring a five-pound (1 pound = 454 g) bag

sweet-ann [11.9K]

The answer is 4567 grams of ice in the five pound bag to specific heat is the -20 degrees! Hope I helped! :)

5 0

2 years ago

The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°C _____. See Co

Klio2033 [76]

Answer:

Specific heat capacity

Explanation:

Heat capacity is defined as amount of the heat supplied or absorbed by the given mass of the material so to make a unit change in the material's temperature.

The SI unit is Joule / kelvin (J/K).

It is an extensive property.

While,

<u>Specific heat capacity is the amount of heat absorbed or lost by one gram of mass of the substance to raise it's temperature by 1°C or 1 K </u>

<u>It is an intensive property. </u>

4 0

2 years ago

An aluminum ion has 13 protons, 14 neutrons, and 10 electrons. What is the charge of the aluminum ion?

Kipish [7]

Answer:

Explanation:

-10 + 13 = +3

-10 IS THE NUMBER OF ELECTRONS

13 IS THE NUMBER OF PROTONS

3 0

2 years ago

a 5L container contains 3 moles of helium and 4 moles of hydrogen at a pressure of 9 atms maintaining a constant T and additiona

Stells [14]

Answer:

7.71 atm

Explanation:

Given the following data:

$V = 5 L$

$n_{He} = 3 mol$

$n_{H_2} = 4 mol$

$p_1 = 9 atm$

$T = const$

According to the ideal gas law, we know that the product between pressure and volume of a gas is equal to the product between moles, the ideal gas law constant and the absolute temperature:

$pV = nRT$

Since the temperature and the ideal gas constant are constants, as well as the fixed container volume of 5 L, we may rearrange the equation as:

$\frac{p}{n}=\frac{RT}{V}=const$

This means for two conditions, we'd obtain:

$\frac{p_1}{n_1}=\frac{p_2}{n_2}$

Given:

$p_1 = 9 atm$

$n_1 = n_{initial total} = n_{He} + n_{H_2} = 3 mol + 4 mol = 7 mol$

$n_2 = n_{final total} = n_{He} + n_{H_2} = 3 mol + 4 mol + 2 mol = 9 mol$

Solve for the final pressure:

$p_2 = p_1\cdot \frac{n_2}{n_1}$

Now, according to the Dalton's law of partial pressures, the partial pressure is equal to the total pressure multiplied by the mole fraction of a component:

$p_{H_2}=\chi_{H_2}p_2$