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rodikova [14]
3 years ago
7

By changing the number of _______ you get the same element that has a different atomic mass. An example of this would be carbon-

12 and carbon-13. This is known as a ____.
Chemistry
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

neutrons, isotope

Explanation:

Isotopes are atoms of the same element with different atomic mass. The difference in atomic mass is as a result of difference in the number of neutrons in the nuclei of the atoms.

Hence, changing the number of neutrons of an atom with result in having different atomic mass but the number of protons and electrons remain the same.

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In making a pizza, which process involves a chemical
Natasha_Volkova [10]

Answer:

baking the dough to form the crust

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3 years ago
A cation with a +4 charge has 26 neutrons and 18 electrons. What is the identity of the element?
Leya [2.2K]

Answer: Titanium has 22 protons

Explanation:  If an atoms donates 4 electrons, it forms cation with charge +4. So original atom have 22 electrons and because atom is neutral, it has 22 protons. Number of neutrons does not matter, there are more neutrons than protons  in heavier atoms.

3 0
2 years ago
D. Energy is lost as body heat by each organism
dimaraw [331]
A and D I’m not sure tho
5 0
3 years ago
A mixture initially contains AA, BB, and CC in the following concentrations: [A][A]A_1 = 0.550 MM , [B][B]B_1 = 1.40 MM , and [C
Alex787 [66]

Answer:

The value of the equilibrium constant KC is 1.244

Explanation:

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.550 M, [B] = 1.40 M, and [C] = 0.600 M. The following reaction occurs and equilibrium is established: A+2B<->C

At equilibrium, [A] = 0.430 M and [C] = 0.720 M. Calculate the value of the equilibrium constant, Kc

Step 1: The balanced equation

A+2B<->C

Step 2: The initial concentrations

[A] = 0.550 M

[B]= 1.40 M

[C] = 0.600 M

Step 3: The concentraions at equilibrium

[A] = 0.550 -X = 0.430 M

[B]= 1.40 -2X M

[C] = 0.600 + X = 0.720 M

X = 0.120 M

[A] = 0.550 - 0.120 = 0.430 M

[B]= 1.40 -2*0.120 =  1.16 M

[C] = 0.600 + 0.120 = 0.720 M

Step 4: Calculate Kc

Kc = [C] / [A][B]²

Kc = 0.720 / (0.430*1.16²)

Kc = 1.244

The value of the equilibrium constant KC is 1.244

5 0
3 years ago
A gas occupies a volume of 650.0 mL when the pressure is 3.50 atm. What will the new volume be if the pressure is reduced to 1.6
Gemiola [76]

The new volume will be 1379 mL.

Explanation:

As per Boyle's law, the product of initial volume and initial pressure of any gas molecule is equal to the product of final volume and final pressure of those molecules.

So here the initial volume is 650 ml and the initial pressure is 3.50 atm. As the temperature is said to be constant, then this system will be obeying Boyle's law. So, the final pressure is given as 1.65 atm. As there is a reduction in the pressure, the volume of the gas is tend to get expanded.

P_{1} V_{1} = P_{2} V_{2}

So, (650*10^{-3}*3.50)=(1.65*V_{2})

V_{2} = \frac{650*10^{-3}*3.50}{1.65} = 1379 mL

So, the new volume of the gas on reduction in pressure is 1379 mL.

7 0
3 years ago
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