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sesenic [268]
2 years ago
9

The light traveled from _____________________ to __________________. (What transparent materials?)

Chemistry
1 answer:
sergiy2304 [10]2 years ago
5 0

Explanation:

High density medium to low density medium.

You might be interested in
Caed for this question.
OLga [1]

Answer:

0.962 atm.

97.4 kPa.

731 torr.

14.1 psi.

97,434.6 Pa.

Explanation:

Hello.

In this case, given the available factors equaling 1 atm of pressure, each required pressure turns out:

- Atmospheres: 1 atm = 760 mmHg:

p=731mmHg*\frac{1atm}{760mmHg} =0.962atm

- Kilopascals:: 101.3 kPa = 760 mmHg:

p=731mmHg*\frac{101.3kPa}{760mmHg} =97.4kPa

- Torrs: 760 torr = 760 mmHg:

p=731mmHg*\frac{760 torr}{760mmHg} =731 torr

- Pounds per square inch: 14.69 psi = 760 mmHg:

p=731mmHg*\frac{14.69}{760mmHg} =14.1psi

- Pascals: 101300 Pa = 760 mmHg:

p=731mmHg*\frac{101300Pa}{760mmHg} \\\\p=97,434.6Pa

Best regards.

5 0
3 years ago
15. You have a solution of .835mol of NaCl in 2.5L of solution, what is the molarity?
Viktor [21]

Answer: 0.334mol/L

Explanation:

M=\frac{mol}{L}

M=\frac{0.835mol}{2.5L} \\M=0.334mol/L

5 0
3 years ago
Type of bond between na+1 ion and Cl-1 ion is ion
makvit [3.9K]

A neutral sodium atom, for example, contains 11 protons and 11 electrons. By removing an electron from this atom we get a positively charged Na+ ion that has a net charge of +1. Atoms that gain extra electrons become negatively charged. A neutral chlorine atom, for example, contains 17 protons and 17 electrons.

6 0
3 years ago
A helium-filled weather balloon has a volume of 793 L at 16.9°C and 759 mmHg. It is released and rises to an altitude of 4.05 km
mariarad [96]
<h3>Answer:</h3>

1082.96 L

<h3>Explanation:</h3>

We are given;

  • Initial volume of helium gas, V1 = 793 L
  • Initial temperature, T1 = 16.9°C

            But, K = °C + 273.15

  • Thus, initial temperature, T1 is 290.05 K
  • Initial pressure, P1 = 759 mmHg
  • New pressure at 4.05 km, P2 = 537 mmHg
  • New temperature at 4.05 km, T2 = 7.1 °C

                                                             = 280.25 K

Assuming we are required to calculate the new volume at the height of 4.05 km

We are going to use the combined gas law.

  • According to the combined gas law;

\frac{P1V1}{T1}=\frac{P2V2}{T2}

  • Rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(759mmHg)(793L)(280.25K)}{(537mmHg)(290.05K)}

V2=1082.96L

Therefore, the new volume of the balloon at the height of 4.05 km is 1082.96 L

6 0
3 years ago
Help with this I need it right now please
alexdok [17]

Answer:

1) F=5×9.8

F=49

2) F=50×9.8

F=490

3) W= fd

W=10×3

W=30

4 0
2 years ago
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