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2 years ago

How can geo thermal energy be used ?

Physics

2 answers:

jek_recluse [69]2 years ago

5 0

Answer:

Geothermal energy can heat, cool, and generate electricity: Geothermal energy can be used in different ways depending on the resource and technology chosen—heating and cooling buildings through geothermal heat pumps, generating electricity through geothermal power plants, and heating structures through direct-use

Explanation:

Tju [1.3M]2 years ago

3 0

geothermal energy, form of energy conversion in which heat energy from within Earth is captured and harnessed for cooking, bathing, space heating, electrical power generation, and other uses. Heat from Earth's interior generates surface phenomena such as lava flows, geysers, fumaroles, hot springs, and mud pots.

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Name the regions of a electromagnetic spectrum from the shortest wavelength to the longest wavelength

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Answer:

From shortest wavelength to longest wavelength:

Gamma Rays

X-Rays

Ultraviolet

Visible Light

Infrared waves

Microwaves

Radio Waves

Explanation:

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3 years ago

A student pushes a chair into a desk. If the student's push is the action force, then what is the reaction force in this example

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Explanation:

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3 years ago

Read 2 more answers

A small block of mass m = 0.032 kg can slide along the frictionless loop-the-loop, with loop radius R = 12 cm. The block is rele

Lunna [17]

Answer:

Part a)

$W = 0.15 J$

Part b)

$W = 0.11 J$

Part c)

$U = 0.19 J$

Part d)

$U = 0.038 J$

Part e)

$U = 0.075 J$

Part f)

It is independent of the speed of the object so all part answers will remain the same

Explanation:

Part a)

As we know that Point P is at height 5R while point Q is at height R

so the work done by gravity from P to Q is given as

$W = mg(5R - R)$

$W = 0.032(9.8)(4)(0.12)$

$W = 0.15 J$

Part b)

When it reaches to the top of the loop then its final height from ground is

h = 2R

so work done from P to Q is given as

$W = mg(5R - 2R)$

$W = 3mgR$

$W = 0.11 J$

Part c)

Potential energy at P point is given as

$U = mgH$

$U = 0.032(9.8)(5)(0.12)$

$U = 0.19 J$

Part d)

Potential energy at Q point is given as

$U = mgH$

$U = 0.032(9.8)(0.12)$

$U = 0.038 J$

Part e)

Potential energy at top point is given as

$U = mgH$

$U = 0.032(9.8)(2)(0.12)$

$U = 0.075 J$

Part f)

Since all the answer from part a) to part e) depends only upon the position of the object.

So here we can say that it is independent of the speed of the object so all part answers will remain the same

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4 years ago

Plz help brainliest<br> plzzzzzzzzzzzzzzzzz!!!!!!!!!!!!!!

Likurg_2 [28]

Answer:

Explanation:

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3 years ago

Chris shoots an arrow up into the air. The height of the arrow is given by the function h(t) = - 16t2 + 32t + 26 where t is the

seropon [69]

Answer:

The maximum height of the arrow is 42 (and the units given for the height)

Explanation:

Everything is easier if you make a graph, you can give values to t and replace that values in the function, for example:

When t=0

$h(0)=-16(0^{2})+32(0)+26$

h(0)=26

If you give some values to t you can see how the trajectory of the arrow is (please look the graphic below)

Now, to find the maximum you have to find the derivative of the function that describes the height of the arrow:

$h(t)=-16t^{2}+32t+26$

$h'(t)=-32t+32$

Then you have to take the derivative, and equals to zero to find t:

-32t+32=0

-32t=32

t=1

That is in the time of 1 second the arrow has its maximum height.

Now you have to replace this value in the original function, to find the height of the arrow:

$h(1)=-16(1^{2})+32(1)+26$

h(1)=-16+32+36

h(1)=42

4 0

3 years ago

How can geo thermal energy be used ?​

How can geo thermal energy be used ?