This question is based on the fundamental assumption of vector direction.
A vector is a physical quantity which has magnitude as well direction for its complete specification.
The magnitude of a physical quantity is simply a numerical number .Hence it can not be negative.
A negative vector is a vector which comes into existence when it is opposite to our assumed direction with respect to any other vector. For instance, the vector is taken positive if it is along + X axis and negative if it is along - X axis.
As per the first option it is given that a vector is negative if its magnitude is greater than 1. It is not correct as magnitude play no role in it.
The second option tells that the magnitude of the vector is less than 1. Magnitude can not be negative. So this is also wrong.
Third one tells that a vector is negative if its displacement is along north. It does not give any detail information about the negativity of a vector.
In a general sense we assume that vertically downward motion is negative and vertically upward is positive. In case of a falling object the motion is vertically downward. So the velocity of that object is negative .
So last option is partially correct as the vector can be negative depending on our choice of co-ordinate system.
Explanation:
The solute does not have to be in the same physical state as the solvent, but the physical state of the solvent usually determines the state of the solution. As long as the solute and solvent combine to give a homogeneous solution, the solute is said to be soluble in the solvent.
1. liquid solution to a. oceans
2. gaseous solution to b. clouds
Not sure about 3 and 4.
3 might be oxygen but I think that's 5. element.
Hope this helps, not sure about water and air though.
The formula for accelerational displacement is at^2/2, so we know that 3.9t^2/2 = 200, or 3.9t^2 = 400. t =
, at = v, so
Answer:
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
Explanation:
Hi there!
The acceleration is defined as the change in velocity in a time:
a = Δv / Δt
Where:
a = acceleration.
Δv = change in velocity = final velocity - initial velocity.
Δt = elapsed time.
In this case:
Initial velocity = 60 mi/h
final velocity = 50 mi/h
elapsed time = 3.0 s
Let´s convert the time unit into h:
3.0 s · 1 h /3600 s = 1/1200 h
Now, let´s calculate the acceleration:
a = Δv / Δt
a = (50 mi/h - 60 mi/h) / 1/1200 h
a = -1.2 × 10⁴ mi/h²
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
